Propane gas at 100°C is compressed isothermally from an initial pressure of 1 bar to a final pressure of 10 bar. Estimate AH and AS. (For data, use the properties of pure species table and the heat capacities of gases in the ideal-gas state table.) The values of the ideal gas constant are given in the table below. (Include a minus sign if required.)

Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
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Propane gas at 100°C is compressed isothermally from an initial pressure of 1 bar to a final pressure of 10 bar. Estimate
AH and AS. (For data, use the properties of pure species table and the heat capacities of gases in the ideal-gas state
table.) The values of the ideal gas constant are given in the table below. (Include a minus sign if required.)
R =
=
=
=
Values of the Universal Gas Constant
82.06 cm³ (atm)-mol-¹ K-¹ = 62, 356 cm³-(torr)-mol-¹.K-¹
1.987 (cal)-mol¹K¹ = 1.986 (Btu) (lb mole)-¹(R)-¹
0.7302 (ft)³ (atm) (lb mol)-¹(R)-¹ = 10.73 (ft)³ (psia) (lb mol)-¹(R)-¹
-1
= 1545 (ft) (lb) (lb mol)-¹(R)-¹
=
8.314 J-mol-¹-K-¹ = 8.314 m³-Pa-mol-¹.K-¹
83.14 cm³-bar-mol-¹.K-¹8314 cm³-kPa-mol-¹-K-¹
The enthalpy change is
The entropy change is
1
J-mol-1
J-mol-¹-K-1
Transcribed Image Text:Propane gas at 100°C is compressed isothermally from an initial pressure of 1 bar to a final pressure of 10 bar. Estimate AH and AS. (For data, use the properties of pure species table and the heat capacities of gases in the ideal-gas state table.) The values of the ideal gas constant are given in the table below. (Include a minus sign if required.) R = = = = Values of the Universal Gas Constant 82.06 cm³ (atm)-mol-¹ K-¹ = 62, 356 cm³-(torr)-mol-¹.K-¹ 1.987 (cal)-mol¹K¹ = 1.986 (Btu) (lb mole)-¹(R)-¹ 0.7302 (ft)³ (atm) (lb mol)-¹(R)-¹ = 10.73 (ft)³ (psia) (lb mol)-¹(R)-¹ -1 = 1545 (ft) (lb) (lb mol)-¹(R)-¹ = 8.314 J-mol-¹-K-¹ = 8.314 m³-Pa-mol-¹.K-¹ 83.14 cm³-bar-mol-¹.K-¹8314 cm³-kPa-mol-¹-K-¹ The enthalpy change is The entropy change is 1 J-mol-1 J-mol-¹-K-1
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