Hello, need the answer for them as soon as possible. thank you Prolog: We are writing bst_member/2, a relation between an integer and a binary search tree containing that integer.bst_member(X, bin(L, X, R)).bst_member(X, bin(L, Y, R)) :- X #< Y, bst_member(X, L).bst_member (X, bin(L, Y, R)) :- X #> Y, bst_member(X, R).Ignoring behavior when the second argument is not a BST, is this definition correct?O No, we have not specified how to handle the empty treeO No, we have not specified what to do when the integer is not presentO Yes, but it will only terminate when both arguments are fully instantiatedO Yes, but it will only terminate when the second argument is structurally instantiatedAll of the aboveNone of the aboveI don't know Logic Programming: A unifier for two terms is a term that is an instance of both terms, meaning it can be obtained by substitution of variables.Given two Prolog terms, foo(A, B) and bar(X, Y), select the term that is a unifier.O foo(A, A)O foo(X, Y)O foobar(A, B, X, Y)O foo(U, V)O All of the aboveO None of the aboveO I don't know

Question 1 The correct answer is option (B) No, we have not specified what to do when the integer is…

Prolog: We are writing bst_member/2, a relation between an integer and a binary search tree containing that integer. bst_member (X, bin(L, X, R)). bst_member (X, bin(L, Y, R)) :- X #< Y, bst_member(X, L). bst_member (X, bin(L, Y, R)) :- X #> Y, bst_member (X, R). Ignoring behavior when the second argument is not a BST, is this definition correct? O No, we have not specified how to handle the empty tree O No, we have not specified what to do when the integer is not present Yes, but it will only terminate when both arguments are fully instantiated O Yes, but it will only terminate when the second argument is structurally instantiated O All of the above O None of the above O I don't know

Prolog: We are writing bst_member/2, a relation between an integer and a binary search tree containing that integer. bst_member (X, bin(L, X, R)). bst_member (X, bin(L, Y, R)) :- X #< Y, bst_member(X, L). bst_member (X, bin(L, Y, R)) :- X #> Y, bst_member (X, R). Ignoring behavior when the second argument is not a BST, is this definition correct? O No, we have not specified how to handle the empty tree O No, we have not specified what to do when the integer is not present Yes, but it will only terminate when both arguments are fully instantiated O Yes, but it will only terminate when the second argument is structurally instantiated O All of the above O None of the above O I don't know

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Question

Hello, need the answer for them as soon as possible. thank you

Prolog: We are writing bst_member/2, a relation between an integer and a binary search tree containing that integer.
bst_member(X, bin(L, X, R)).
bst_member(X, bin(L, Y, R)) :- X #< Y, bst_member(X, L).
bst_member (X, bin(L, Y, R)) :- X #> Y, bst_member(X, R).
Ignoring behavior when the second argument is not a BST, is this definition correct?
O No, we have not specified how to handle the empty tree
O No, we have not specified what to do when the integer is not present
O Yes, but it will only terminate when both arguments are fully instantiated
O Yes, but it will only terminate when the second argument is structurally instantiated
All of the above
None of the above
I don't know

Logic Programming: A unifier for two terms is a term that is an instance of both terms, meaning it can be obtained by substitution of variables.
Given two Prolog terms, foo(A, B) and bar(X, Y), select the term that is a unifier.
O foo(A, A)
O foo(X, Y)
O foobar(A, B, X, Y)
O foo(U, V)
O All of the above
O None of the above
O I don't know

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