{(r, y) E R? : (x, y) = a(1, – 1), a ER}. Since M isa O, of R?, we can apply Projection theorem. Thus, for any u E R?, there exist u E Mu1 + u2. Here, MI = {(x, y) E R? : (x, y) = a(0,), a E R}.(03) E M andProblem 2. In R2, we set M =and u2 E Mt such that u=Moreover, set u =(4, 0). Then, u E R? and u is decomposed by uU2 = (04) E M+.Please fill in 0. Concerning 02, please write a simple answer.

Answered: Image /qna-images/answer/765d1ce8-4289-49e7-8227-9163cd5fa45a.jpg

Answered: Projection theorem.

Math

Advanced Math

Projection theorem.

Advanced Engineering Mathematics

10th Edition

ISBN:9780470458365

Author:Erwin Kreyszig

Publisher:Erwin Kreyszig

Chapter2: Second-order Linear Odes

Section: Chapter Questions

Problem 1RQ

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