Project 1: Caesar Cipher Assignment Overview In this assignment, we are going to implement a simple encoding and decoding of text. As a result of working on this project, you will gain more experience with the use of: 1. string 2. if statement 3. for loop and while loop Background A rotation cipher is one of the simplest, plain-text ciphers, known since at least the time of Julius Caesar. It takes in a plain-text string, and translates it into a new string based on a rotation of the alphabet being used. The basis is a "rotation", a re-sequencing of an alphabet. Consider the following example. Consider the alphabet being a single string consisting of the lower case English letters as below (shown with each letter's associated index):
Project 1: Caesar Cipher Assignment Overview In this assignment, we are going to implement a simple encoding and decoding of text. As a result of working on this project, you will gain more experience with the use of: 1. string 2. if statement 3. for loop and while loop Background A rotation cipher is one of the simplest, plain-text ciphers, known since at least the time of Julius Caesar. It takes in a plain-text string, and translates it into a new string based on a rotation of the alphabet being used. The basis is a "rotation", a re-sequencing of an alphabet. Consider the following example. Consider the alphabet being a single string consisting of the lower case English letters as below (shown with each letter's associated index):
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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Question
How to develop a flowchart for Caesar cipher ? On paper
Expert Solution
Step 1
Answer:
Code:
def enc():
text,s=input("Enter the string to be encoded: "),int(input("Enter the shift value(1-25): "))
result = ""
# transverse the plain text
for i in range(len(text)):
char = text[i]
# Encrypt uppercase characters in plain text
if (char.islower()):
result += chr((ord(char) + s - 97) % 26 + 97)
# Ignore rest
else:
result += char
print("Encrypted text: ",result)
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