program
Q: C++
A: Coded using C++.
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When the following program is run, assume that the user enters 40000000000 for the large integer. What will print? When it is run again, assume the user enters 30000. What prints this time? Explain why the program prints what it does. Assume that the value of INT_MAX is 2147483647.
#include <iostream>
#include <limits.h>
using namespace std;
int main()
{
int x,y;
cout<<"Enter a large integer\n";
cin>>x; y=INT_MAX;
if(x>INT_MAX)
cout<<"x is larger than INT_MAX\n";
else cout<<"x is smaller than INT_MAX\n";
return 0;
}
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- in the following code there is * #include #include int man() { int B=25; int *p; //b memory location=1234; p=&b; cout>> b; gtch(); return 0; 2 error no error 3 error 4 errorTask: Remove all asterisks (*) in the codes and use typedef int* IntPtr instead, and make it run with the same output. Code: #include using namespace std; int main() { int *p1, *p2; p1 = new int; *p1 = 42; p2 = p1; cout << "*p1 == " << *p1 << endl; cout << "*p2 == " << *p2 << endl; *p2 = 53; cout << "*p1 == " << *p1 << endl; cout << "*p2 == " << *p2 << endl; p1 = new int; *p1 = 88; cout << "*p1 == " << *p1 << endl; cout << "*p2 == " << *p2 << endl; return 0; }# We have small bags of cement (10 kilograms each)# We have big bags of cement (50 kilograms each)# Return the number of each of the bags to use,# assuming we always use big bags before small bags.# Return -1 for each if it can't be done.## Oh, and there 4 errors in the main() function# Happy Debugging! import random def main():keep_going = "y" while keepgoing.upper() == "Y": small_bags = random.randint(5,20) big_bags = random.randint(1,5) goal = random.randint(60,350,10) small_used, big_used = make_cemont(small_bags, big_bags, gaol)if small_used == -1: print("Sorry, we can't reach", goal, "kilograms with", small_bags, "small bags and", big_bags, "big bags.")else: print("Goal", goal, "kilograms achieved!") print("Small bags:", small_used, "out of", small_bags) print(" Big bags:", big_used, "out of", big_bags) another_round = input("Try again (y/n)?: ")def make_cement(small_bags_supplied, big_bags_supplied,…
- Refer to the statement below, #include void main() { int i; int number[11]={12,15,17,3,2,7,10,10,15,15,50}; for(i=0;i < 11; į++){ printf(" %d", number[i]); } Write a segment in C language to: Compute the average number Find the maхітит аnd minimum питberProgram C Loop, pls help ASAP int getNum(); /*accepts input from the user.*/ void display(int num); /*prints the number pattern*/ ---------------------------------------------------------------------(16) 6. You want to write a Java application that creates a while loop that runs until the user enters a 0 as input. Each time the while loop runs, it displays a menu of three choices as will be shown in the sample run below. When the program reads in the user's choice, that choice should be read in as a String called choiceStr. Then, choiceStr should be converted into an int called choice by using the code below: int choice Integer.parseInt(choiceStr); If the user enters a 1 for choice == 1, the program will print "Choice 1" to the screen. If the user enters a 2 for choice == 2, the program will print "Choice 2" to the screen. Here is a sample run: 0 - to quit 1 to print Choice 1 2 to print Choice 2 Enter choice: 1 Choice 1 0 - to quit 1 to print Choice 1 2 to print Choice 2 Enter choice: 1 Choice 1 0 to quit 1 to print Choice 1 2 to print Choice 2 Enter choice: 2 Choice 2 0 - to quit 1 to print Choice 1 2 to print Choice 2 Enter choice: 0
- // LargeSmall.cpp - This program calculates the largest and smallest of three integer values. #include <iostream> using namespace std; int main() { // This is the work done in the housekeeping() function // Declare and initialize variables here int largest; // Largest of the three values int smallest; // Smallest of the three values // Prompt the user to enter 3 integer values // Write assignment, add conditional statements here as appropriate // This is the work done in the endOfJob() function // Output largest and smallest number. cout << "The largest value is " << largest << endl; cout << "The smallest value is " << smallest << endl; return 0; }Part 4: Working with Logic Errors: Working with Logic Errors // This program takes two values from the user and then swaps them// before printing the values. The user will be prompted to enter// both numbers.// Place your name here#include <iostream>using namespace std; int main(){float firstNumber;float secondNumber;// Prompt user to enter the first number.cout << "Enter the first number" << endl;cout << "Then hit enter" << endl;cin >> firstNumber;// Prompt user to enter the second number.cout << "Enter the second number" << endl;cout << "Then hit enter" << endl;cin >> secondNumber;// Echo print the input.cout << endl << "You input the numbers as " << firstNumber<< " and " << secondNumber << endl;// Now we will swap the values.firstNumber = secondNumber;secondNumber = firstNumber;// Output the values.cout << "After swapping, the values of the two numbers are "<<…#include <iostream> #include <cmath> using namespace std; // declare functions void display_menu(); void convert_temp(); double to_celsius(double fahrenheit); double to_fahrenheit(double celsius); int main() { cout << "Convert Temperatures\n\n"; display_menu(); char again = 'y'; while (again == 'y') { convert_temp(); cout << "Convert another temperature? (y/n): "; cin >> again; cout << endl; } cout << "Bye!\n"; } // define functions void display_menu() { cout << "MENU\n" << "1. Fahrenheit to Celsius\n" << "2. Celsius to Fahrenheit\n\n"; } void convert_temp() { int option; cout << "Enter a menu option: "; cin >> option; double f = 0.0; double c = 0.0; switch (option) { case 1: cout << "Enter degrees Fahrenheit: "; cin >> f; c =…
- Need help only with the highlighted part no need for help with the code the code is just for reference #include <stdio.h> int printBin(int value); int main(){ int num=10; int tobinary= printBin(num); printf("The number %d converted to binary as %d",num,tobinary); unsigned int x = 1; char *ccc = (char*)&x; if(*ccc){ printf("This is Little endian"); } else{ printf("This is Big endian"); } getchar(); return 0; } int printBin(int value) { if(value<2) return value; return printBin(value / 2) *10 + value % 2; }