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Program 2 - Translate the following C program to Pep/9 assembly language. #include const int limit = 5; int main() { int number; scanf("%d", &number); while (number < limit) { number++; printf("%d ", number); } return 0; }

Program 2 - Translate the following C program to Pep/9 assembly language. #include const int limit = 5; int main() { int number; scanf("%d", &number); while (number < limit) { number++; printf("%d ", number); } return 0; }

Computer Networking: A Top-Down Approach (7th Edition)
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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I cant tell why this code isnt compiling in Pep/9

BR   Main
Limit : . EQUATE 5
number: . EQUATE O ; Local Variable# 1c
Main : SUB SP1 , I ; push # number
number : . BLOCK 2
LDBA  intIN, d ; scant ("%d", & number)
STDB  number, d
LDBA number, d ; while ( numbers < Limit )
ADDA 1, ;
STWA number ,d
BR while
endwh : STOP
. END

 

Program 2 - Translate the following C program to Pep/9 assembly language. #include <stdio.h> const int limit = 5; int main() { int number; scanf("%d", &number); while (number < limit) { number++; printf("%d ", number); } return 0; }
Transcribed Image Text:Program 2 - Translate the following C program to Pep/9 assembly language. #include <stdio.h> const int limit = 5; int main() { int number; scanf("%d", &number); while (number < limit) { number++; printf("%d ", number); } return 0; }
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