Professors collected data consisting of eye color and gender of statistics students. Among 888 male students, 268 had blue eyes. Among 1135 female students, 441 had blue eyes. Use a 0.01 significance level to test the claim that the proportions of blue eyes are the same for males and females. Complete parts (a) through (c) below. Consider the first sample to be the sample of males and the second sample to be the sample of females. a. Test the claim using a hypothesis test. What are the null and alternative hypotheses for the hypothesis test? OC. Ho: P1 = P2 H1: Pp # P2 O B. Ho: P, SP2 H1: P1 # P2 O E. Ho: P, +P2 H1: P1 = P2 O A. Ho: P1 = P2 H1: P1 > P2 O D. Ho: P1 = P2 H1: P1

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Professors collected data consisting of eye color and gender of statistics students. Among 888 male students, 268 had blue eyes. Among 1135 female students,
441 had blue eyes. Use a 0.01 significance level to test the claim that the proportions of blue eyes are the same for males and females. Complete parts (a) through
(c) below. Consider the first sample to be the sample of males and the second sample to be the sample of females.
a. Test the claim using a hypothesis test.
What are the null and alternative hypotheses for the hypothesis test?
O A. Hg: P1 = P2
H1: P1 > P2
O B. Ho: P1 S P2
H1: P1 + P2
O C. Ho: P1 = P2
H1: P1 + P2
O D. Ho: P1 = P2
H1: P1< P2
O E. Ho: P1 + P2
H1: P1 = P2
OF. Ho: P1 2 P2
H1: P1 + P2
Transcribed Image Text:Professors collected data consisting of eye color and gender of statistics students. Among 888 male students, 268 had blue eyes. Among 1135 female students, 441 had blue eyes. Use a 0.01 significance level to test the claim that the proportions of blue eyes are the same for males and females. Complete parts (a) through (c) below. Consider the first sample to be the sample of males and the second sample to be the sample of females. a. Test the claim using a hypothesis test. What are the null and alternative hypotheses for the hypothesis test? O A. Hg: P1 = P2 H1: P1 > P2 O B. Ho: P1 S P2 H1: P1 + P2 O C. Ho: P1 = P2 H1: P1 + P2 O D. Ho: P1 = P2 H1: P1< P2 O E. Ho: P1 + P2 H1: P1 = P2 OF. Ho: P1 2 P2 H1: P1 + P2
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