Professor X wants to compare a new approach to his teaching style.  24 students are matched according to their prior background and academic performance.  One member of each pair is assigned to a class using his traditional teaching and the other to a class using his new teaching approach.  At the end of the course, the level of learning is determined by an examination.  The Dean of the business school wants to know if the students using the new approach learned more than those using traditional approach.  Test at the 5% level of significance. To answer this question, Dr. Card ran several analyses and provided the out below.  Note that none of these analyses might be correct.  What is the correct hypothesis test for this problem? A. H0: (μ1 - μ2) = 0     H1: (μ1 - μ2) > 0 B.  H0: μD = 0     H1: μD > 0 C. H0: μD = 0     H1: μD < 0 D. H0: (μ1 - μ2) = 0       H1: (μ1 - μ2) < 0    What is the conclusion? A. Do Not Reject H0 and conclude that students using the new approach learned more B. Reject H0 and conclude that students using the new approach learned more C. Reject H0 and conclude that students using the traditional approach learned more D. Do Not Reject H0 and conclude students using the traditional approach learned more

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Professor X wants to compare a new approach to his teaching style.  24 students are matched according to their prior background and academic performance.  One member of each pair is assigned to a class using his traditional teaching and the other to a class using his new teaching approach.  At the end of the course, the level of learning is determined by an examination.  The Dean of the business school wants to know if the students using the new approach learned more than those using traditional approach.  Test at the 5% level of significance. To answer this question, Dr. Card ran several analyses and provided the out below.  Note that none of these analyses might be correct. 

What is the correct hypothesis test for this problem?

A. H0: (μ1 - μ2) = 0

    H1: (μ1 - μ2) > 0

B.  H0: μD = 0

    H1: μD > 0

C. H0: μD = 0

    H1: μD < 0

D. H0: (μ1 - μ2) = 0  

    H1: (μ1 - μ2) < 0 

 

What is the conclusion?

A. Do Not Reject H0 and conclude that students using the new approach learned more

B. Reject H0 and conclude that students using the new approach learned more

C. Reject H0 and conclude that students using the traditional approach learned more

D. Do Not Reject H0 and conclude students using the traditional approach learned more

t-Test: Paired Two Sample for Means
Traditional
New
F-Test Two-Sample for Variances
Mean
82.33333 85.83333
Variance
96.24242 108.3333
12
0.89892
Traditional
New
Observations
Pearson Correlation
12
85.83333
Mean
Variance
Observations
82.33333
96.24242
Hypothesized Mean
Df
108.3333
12
12
11
df
F
11
11
t Stat
P(T<=t) one-tail
t Critical one-tail
P(T<=t) two-tail
t Critical two-tail
-2.64575
0.202761468
0.011379
1.795885
P(F<=f) one-
0.039
F Critical one-
0.791552339
0.022758
2.200985
t-Test: Two-Sample Assuming Unequal Variances
-Test: Two-Sample Assuming Equal Variances
Traditional
New
Traditional
New
Mean
82.33333 85.83333
82.33333
96.24242
Mean
85.83333
108.3333
Variance
96.24242 108.3333
12
Variance
Observations
Pooled Variance
12
Observations
12
12
102.2879
Hypothesized Mean
df
t Stat
Hypothesized Mean
Df
tStat
P(T<=t) one-tail
t Critical one-tail
P(T<=t) two-tail
t Critical two-tail
11
-3.61031562
-1.04575
P(T<=t) one-tail
t Critical one-tail
P(T<=t) two-tail
t Critical two-tail
0.018586284
0.121379
1.795885
2.339885067
0.037172567
0.242758
2.593694267
2.200985
Transcribed Image Text:t-Test: Paired Two Sample for Means Traditional New F-Test Two-Sample for Variances Mean 82.33333 85.83333 Variance 96.24242 108.3333 12 0.89892 Traditional New Observations Pearson Correlation 12 85.83333 Mean Variance Observations 82.33333 96.24242 Hypothesized Mean Df 108.3333 12 12 11 df F 11 11 t Stat P(T<=t) one-tail t Critical one-tail P(T<=t) two-tail t Critical two-tail -2.64575 0.202761468 0.011379 1.795885 P(F<=f) one- 0.039 F Critical one- 0.791552339 0.022758 2.200985 t-Test: Two-Sample Assuming Unequal Variances -Test: Two-Sample Assuming Equal Variances Traditional New Traditional New Mean 82.33333 85.83333 82.33333 96.24242 Mean 85.83333 108.3333 Variance 96.24242 108.3333 12 Variance Observations Pooled Variance 12 Observations 12 12 102.2879 Hypothesized Mean df t Stat Hypothesized Mean Df tStat P(T<=t) one-tail t Critical one-tail P(T<=t) two-tail t Critical two-tail 11 -3.61031562 -1.04575 P(T<=t) one-tail t Critical one-tail P(T<=t) two-tail t Critical two-tail 0.018586284 0.121379 1.795885 2.339885067 0.037172567 0.242758 2.593694267 2.200985
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