Prof. Modyn proposes a multi-step, steady-state approach to cooling low-pressure steam before it's exhausted to the ambient. The steam enters a compressor at 1.50 kg/s, 0.100 MPa, and 285 °C where it is adiabatically compressed to 1.20 MPa requiring 2550 kW. The water is then feed to a well-insulated counter-current heat exchanger where it is isobarically cooled with air flowing at 1.14 kmol/s. The air enters the exchanger at 25.0 °C and leaves at 185 °C. Lastly, the water is fed to a well-insulated throttle valve where it is reduced back to 0.100 MPa forming a 2-phase product. Neglect changes in kinetic and potential energy. Assume air is an ideal gas with Ĉp [kJ/kmol·K] = 27.9 + 4.78 x 10-³T with T in K. Calculate the heat interaction term of the air, Qair (kW). 5418.53 kW Calculate the exiting enthalpy of the water, he,water (kJ/kg). 605.2 kJ/kg Incorrect Calculate the mass flow rate of liquid water recovered in the process, mļig (kg/s).

Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
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Prof. Modyn proposes a multi-step, steady-state approach to cooling low-pressure steam before it's exhausted to the ambient.
The steam enters a compressor at 1.50 kg/s, 0.100 MPa, and 285 °C where it is adiabatically compressed to 1.20 MPa requiring
2550 kW. The water is then feed to a well-insulated counter-current heat exchanger where it is isobarically cooled with air
flowing at 1.14 kmol/s. The air enters the exchanger at 25.0 °C and leaves at 185 °C. Lastly, the water is fed to a well-insulated
throttle valve where it is reduced back to 0.100 MPa forming a 2-phase product. Neglect changes in kinetic and potential energy.
Assume air is an ideal gas with Ốp [kJ/kmol·K] = 27.9 + 4.78 x 10-3T with Tin K.
Calculate the heat interaction term of the air, Qair (kW).
5418.53
kW
Calculate the exiting enthalpy of the water, hewater (kJ/kg).
605.2
kJ/kg
Incorrect
Calculate the mass flow rate of liquid water recovered in the process, mlig (kg/s).
1.38
kg/s
Incorrect
Transcribed Image Text:Prof. Modyn proposes a multi-step, steady-state approach to cooling low-pressure steam before it's exhausted to the ambient. The steam enters a compressor at 1.50 kg/s, 0.100 MPa, and 285 °C where it is adiabatically compressed to 1.20 MPa requiring 2550 kW. The water is then feed to a well-insulated counter-current heat exchanger where it is isobarically cooled with air flowing at 1.14 kmol/s. The air enters the exchanger at 25.0 °C and leaves at 185 °C. Lastly, the water is fed to a well-insulated throttle valve where it is reduced back to 0.100 MPa forming a 2-phase product. Neglect changes in kinetic and potential energy. Assume air is an ideal gas with Ốp [kJ/kmol·K] = 27.9 + 4.78 x 10-3T with Tin K. Calculate the heat interaction term of the air, Qair (kW). 5418.53 kW Calculate the exiting enthalpy of the water, hewater (kJ/kg). 605.2 kJ/kg Incorrect Calculate the mass flow rate of liquid water recovered in the process, mlig (kg/s). 1.38 kg/s Incorrect
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