Produce a Punnett square to illustrate the dihybrid cross described below (NOTE: It is the same story as in question 9, above so you may use the square that you produced in answer to question 9 to answer this question, you do not need to draw it twice). use it to fill in the blanks in the answer text below. NOTE: please type in whole numbers only, no symbols, no letters, no spaces. There are two common alleles for the TAS2R38 gene on Chromosome 7. This gene encodes a seven-transmembrane G-protein coupled receptor. This receptor controls the ability to taste glucosinolates. Phenylthiocarbamide (PTC) is a synthetic glucosinolate. The recessive TAS2R38 allele produces a non-functional receptor. The father in this dihybrid cross is heterozygous for these alleles, meaning that he can taste PTC. The mother is homozygous recessive, meaning that she cannot taste PTC The father has X-Linked Protoporphyria which means that he is very sensitive to sunlight exposure, he is hemizygous for the dominant causative mutation. The mother is homozygous wild type at the same locus. ANSWER: In the Dihybrid cross described above Blank 1 percent of female offspring are expected to be able to taste PTC. Blank 2 percent of all offspring are expected to be sensitive to sunlight exposure as a consequence of inheriting the X-linked protoporphyria from their father. If the couple in this story have eight children then the number of children expected to be light sensitive, PTC tasting girls is Blank 3. Blank 1 Blank 2 Blank 3 Add your answer Add your answer Add your answer

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Produce a Punnett square to illustrate the dihybrid cross described below (NOTE: It is the same story as in question 9, above
so you may use the square that you produced in answer to question 9 to answer this question, you do not need to draw it
twice). use it to fill in the blanks in the answer text below. NOTE: please type in whole numbers only, no symbols, no
letters, no spaces.
There are two common alleles for the TAS2R38 gene on Chromosome 7. This gene encodes a seven-transmembrane G-protein coupled
receptor. This receptor controls the ability to taste glucosinolates. Phenylthiocarbamide (PTC) is a synthetic glucosinolate. The
recessive TAS2R38 allele produces a non-functional receptor. The father in this dihybrid cross is heterozygous for these alleles,
meaning that he can taste PTC. The mother is homozygous recessive, meaning that she cannot taste PTC
The father has X-Linked Protoporphyria which means that he is very sensitive to sunlight exposure, he is hemizygous for the dominant
causative mutation. The mother is homozygous wild type at the same locus.
ANSWER: In the Dihybrid cross described above Blank 1 percent of female offspring are expected to be able to taste
PTC. Blank 2 percent of all offspring are expected to be sensitive to sunlight exposure as a consequence of inheriting
the X-linked protoporphyria from their father. If the couple in this story have eight children then the number of
children expected to be light sensitive, PTC tasting girls is Blank 3.
Blank 1
Blank 2
Blank 3
Add your answer
Add your answer
Add your answer
Transcribed Image Text:Produce a Punnett square to illustrate the dihybrid cross described below (NOTE: It is the same story as in question 9, above so you may use the square that you produced in answer to question 9 to answer this question, you do not need to draw it twice). use it to fill in the blanks in the answer text below. NOTE: please type in whole numbers only, no symbols, no letters, no spaces. There are two common alleles for the TAS2R38 gene on Chromosome 7. This gene encodes a seven-transmembrane G-protein coupled receptor. This receptor controls the ability to taste glucosinolates. Phenylthiocarbamide (PTC) is a synthetic glucosinolate. The recessive TAS2R38 allele produces a non-functional receptor. The father in this dihybrid cross is heterozygous for these alleles, meaning that he can taste PTC. The mother is homozygous recessive, meaning that she cannot taste PTC The father has X-Linked Protoporphyria which means that he is very sensitive to sunlight exposure, he is hemizygous for the dominant causative mutation. The mother is homozygous wild type at the same locus. ANSWER: In the Dihybrid cross described above Blank 1 percent of female offspring are expected to be able to taste PTC. Blank 2 percent of all offspring are expected to be sensitive to sunlight exposure as a consequence of inheriting the X-linked protoporphyria from their father. If the couple in this story have eight children then the number of children expected to be light sensitive, PTC tasting girls is Blank 3. Blank 1 Blank 2 Blank 3 Add your answer Add your answer Add your answer
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