QUESTION 5Procopio is driving a car (m = 1000 kg) at v7 = 11.11 m/s when he stepped on the brakes. The car traveled a distance of s = 15 m before stoppingcompletely. How much force Fwas needed to stop the car?The work done by the force Fas the car traveled a distance s before stopping is:W =By the work-energy theorem:W =- K1 = -2Combining these two equations for work and isolating F, we obtain an expression for F:F =2Plugging in values, we know that 4114.4 newtons of force is needed to stop the car.

Given: The mass of car is m=1000 kg. The initial velocity of car is v1=11.11 m/s. The distance…

Procopio is driving a car (m = 1000 kg) at v7 = 11.11 m/s when he stepped on the brakes. The car traveled a distance of s = 15 m before stopping completely. How much force Fwas needed to stop the car?

Procopio is driving a car (m = 1000 kg) at v7 = 11.11 m/s when he stepped on the brakes. The car traveled a distance of s = 15 m before stopping completely. How much force Fwas needed to stop the car?

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Question

Expert Solution

Step 1

Given:

The mass of car is $m = 1000 kg$ .
The initial velocity of car is $v_{1} = 11.11 m / s$ .
The distance travelled by car is $s = 15 m$ .
The final velocity of car is $v_{2} = 0 m / s$ .

The formula to calculate the work done by force is,

$W = F s$

Here, W is the work done, F is the force applied and s is the distance travelled.

The formula to calculate the initial kinetic energy of the car is,

$K_{1} = \frac{1}{2} m v_{1}^{2}$

Here, K₁ is the initial kinetic energy, m is the mass and v₁ is the initial velocity of car.

The formula to calculate the final kinetic energy of the car is,

$K_{2} = \frac{1}{2} m v_{2}^{2}$

Here, K₂ is the final kinetic energy and v₂ is the final velocity of car.

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