Procopio is driving a car (m = 1000 kg) at v7 = 11.11 m/s when he stepped on the brakes. The car traveled a distance of s = 15 m before stopping completely. How much force Fwas needed to stop the car?

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QUESTION 5
Procopio is driving a car (m = 1000 kg) at v7 = 11.11 m/s when he stepped on the brakes. The car traveled a distance of s = 15 m before stopping
completely. How much force Fwas needed to stop the car?
The work done by the force Fas the car traveled a distance s before stopping is:
W =
By the work-energy theorem:
W =
- K1 = -2
Combining these two equations for work and isolating F, we obtain an expression for F:
F =
2
Plugging in values, we know that 411
4.4 newtons of force is needed to stop the car.
Transcribed Image Text:QUESTION 5 Procopio is driving a car (m = 1000 kg) at v7 = 11.11 m/s when he stepped on the brakes. The car traveled a distance of s = 15 m before stopping completely. How much force Fwas needed to stop the car? The work done by the force Fas the car traveled a distance s before stopping is: W = By the work-energy theorem: W = - K1 = -2 Combining these two equations for work and isolating F, we obtain an expression for F: F = 2 Plugging in values, we know that 411 4.4 newtons of force is needed to stop the car.
Expert Solution
Step 1

Given:

  • The mass of car is m=1000 kg.
  • The initial velocity of car is v1=11.11 m/s.
  • The distance travelled by car is s=15 m.
  • The final velocity of car is v2=0 m/s.

The formula to calculate the work done by force is,

W=Fs

Here, W is the work done, F is the force applied and s is the distance travelled.

The formula to calculate the initial kinetic energy of the car is,

K1=12mv12

Here, K1 is the initial kinetic energy, m is the mass and v1 is the initial velocity of car.

The formula to calculate the final kinetic energy of the car is,

K2=12mv22

Here, K2 is the final kinetic energy and v2 is the final velocity of car.

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