Processi Governing Equations FBD 25 ΣΕx-max ΣΕ May KD Juntsiy Soln Fx² Ng 4 Ma it's br G MM=IX w = 70 lbf 4 = 47 M₂=0.3 M₁=0,2 Find: Smalest P for motion, acceleration if Plincreased slightly, Normal forces at A,B when moving. ZFx = max fat fr - P = 0 [Fy=mo N₁+ N₂-w=0 N₁ = N₁₂ IM I PLH-2,5€+) = N₂₁ · 1₁5f + + f₁ + fB = 0 P(-2.5f+)-1.5 Ft + P Plh-2.57++1)-1.544 = 0 = 0! P=1.5%+ -2.5+1 29112=2
Processi Governing Equations FBD 25 ΣΕx-max ΣΕ May KD Juntsiy Soln Fx² Ng 4 Ma it's br G MM=IX w = 70 lbf 4 = 47 M₂=0.3 M₁=0,2 Find: Smalest P for motion, acceleration if Plincreased slightly, Normal forces at A,B when moving. ZFx = max fat fr - P = 0 [Fy=mo N₁+ N₂-w=0 N₁ = N₁₂ IM I PLH-2,5€+) = N₂₁ · 1₁5f + + f₁ + fB = 0 P(-2.5f+)-1.5 Ft + P Plh-2.57++1)-1.544 = 0 = 0! P=1.5%+ -2.5+1 29112=2
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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I have been having trouble calculating this. Trying to find the acceleration of P is increased and the normal forces when moving
![Processi
Governing Equations
FBD
25
2)
ΣFx=max Σ F₂ = may
KD
-P
4
W
JE NE
NA
MALDA
علی
5.
G
XI=W3
w = 70 lbf
th=4
M₁ = 0.3
M=0,2
Find: smalest P for motion, acceleration if Pincreased slightly, Normal
forces at A,B when moving.
Solni
[Fx = max ² fat fr - P = 0
[Fy=mary Na+ N₂-w=0 NA=NB
IM I PLH-2,5€+) = N₁₂ · 1₁5f + + f₁ + fB = 0
P(-2.5 f+)-2·1.5 ft + P²"
Plb-2.57++))-2-1.544
=
P = 1.5%+
-2.5+1
29112=2](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F919fc4f8-bc37-4123-8b2a-9ca8cd02385f%2F5c97f50b-6283-4c16-a620-18e2c9d440e9%2Fu39cqna_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Processi
Governing Equations
FBD
25
2)
ΣFx=max Σ F₂ = may
KD
-P
4
W
JE NE
NA
MALDA
علی
5.
G
XI=W3
w = 70 lbf
th=4
M₁ = 0.3
M=0,2
Find: smalest P for motion, acceleration if Pincreased slightly, Normal
forces at A,B when moving.
Solni
[Fx = max ² fat fr - P = 0
[Fy=mary Na+ N₂-w=0 NA=NB
IM I PLH-2,5€+) = N₁₂ · 1₁5f + + f₁ + fB = 0
P(-2.5 f+)-2·1.5 ft + P²"
Plb-2.57++))-2-1.544
=
P = 1.5%+
-2.5+1
29112=2
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