Procedure for square root - Similar to division restoring method 91 92 93 94 1 0 1 =Q = 13 10 10 10 01 = A = 169 01 Subtract first test value 01 01 Answer positive; let q, = 1 01 10 Bring down next pair 01 01 Subtract second test value 0q,01 00 01 Answer positive; let q, = 1 00 01 10 Bring down next pair 00 11 01 Subtract third test value 00q, q,01 negative Answer negative; let q, = 0 00 01 10 Restore partial remainder 00 01 10 01 00 01 10 01 Bring down next pair Subtract fourth test value 000q,q;q,01 Remainder = 00 00 0 Answer positive (zero); let q, =1 %3D

Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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I need a cpp or c code for this algorithm input will be taken by user.
Procedure for square root - Similar to division restoring method
91 92 93 94
1
1
0 1
=Q = 13
10 10 10 01
= A = 169
01
Subtract first test value 01
01
Answer positive; let q, = 1
01 10
01 01
Bring down next pair
Subtract second test value Oq 01
00 01
Answer positive; let q, = 1
00 01 10
Bring down next pair
Subtract third test value 00q,q,01
00 11 01
negative
Answer negative; let q, = 0
00 01 10
Restore partial remainder
00 01 10 01
Bring down next pair
00 01 10 01
Subtract fourth test value 000q,qq01
Remainder = 00 00 0
Answer positive (zero); let q, =1
Transcribed Image Text:Procedure for square root - Similar to division restoring method 91 92 93 94 1 1 0 1 =Q = 13 10 10 10 01 = A = 169 01 Subtract first test value 01 01 Answer positive; let q, = 1 01 10 01 01 Bring down next pair Subtract second test value Oq 01 00 01 Answer positive; let q, = 1 00 01 10 Bring down next pair Subtract third test value 00q,q,01 00 11 01 negative Answer negative; let q, = 0 00 01 10 Restore partial remainder 00 01 10 01 Bring down next pair 00 01 10 01 Subtract fourth test value 000q,qq01 Remainder = 00 00 0 Answer positive (zero); let q, =1
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