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Problems from Schaum's Solved Problem Series Fluid Mechanics and Hydraulics Authors: Jack Evett,Cheng Liu, McGraw Hill

Problems from Schaum's Solved Problem Series Fluid Mechanics and Hydraulics Authors: Jack Evett,Cheng Liu, McGraw Hill

Structural Analysis
Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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1.25 Please help explain the solution and what theories used thanks!
Problems from Schaum's Solved Problem Series Fluid Mechanics and Hydraulics Authors: Jack Evett,Cheng Liu, McGraw Hill Calculate the pressure, in kPa, at A, B, C, and D in Fig. 2-8. PA=-(0.4+0.4)(9.790) = -7.832 kPa; Pa (0.5)(9.790) 4.895 kPa. Neglecting air, Pc Pa=4.895 kPa; Pp 4.895+(0.9)(9.790)(1+0.5+0.4) 21.636 kPa. Air Air 0.4m 0.4m Oil S. S. 0.9 0.5m Fig. 2-8 The air-oil-water system shown in Fig. 2-13 is at 70 °F. If gage A reads 16.1 lb/in abs and gage B reads 2.00 lb/in less than gage C, compute (a) the specific weight of the oil and (b) the reading of gage C. I (a) (16.1)(144) + (0.0750)(3) + (You)(2) =Pa, Pa +(You)(2) + (62.4)(3) =Pc. Since Pc-Pa=2.00, (You)(2) +(62.4)(3) = (2.00)(144), Yoil = 50.4 lb/ft. (b) (16.1)(144) + (0.0750)(3) + (50.4)(2) Pa. P=2419 lb/ft; Pc=2419 + (2.00)(144) = 2707 lb/ft, or 18.80 lb/in?. %3D %3D 16.1 Ib /in? abs
Transcribed Image Text:Problems from Schaum's Solved Problem Series Fluid Mechanics and Hydraulics Authors: Jack Evett,Cheng Liu, McGraw Hill Calculate the pressure, in kPa, at A, B, C, and D in Fig. 2-8. PA=-(0.4+0.4)(9.790) = -7.832 kPa; Pa (0.5)(9.790) 4.895 kPa. Neglecting air, Pc Pa=4.895 kPa; Pp 4.895+(0.9)(9.790)(1+0.5+0.4) 21.636 kPa. Air Air 0.4m 0.4m Oil S. S. 0.9 0.5m Fig. 2-8 The air-oil-water system shown in Fig. 2-13 is at 70 °F. If gage A reads 16.1 lb/in abs and gage B reads 2.00 lb/in less than gage C, compute (a) the specific weight of the oil and (b) the reading of gage C. I (a) (16.1)(144) + (0.0750)(3) + (You)(2) =Pa, Pa +(You)(2) + (62.4)(3) =Pc. Since Pc-Pa=2.00, (You)(2) +(62.4)(3) = (2.00)(144), Yoil = 50.4 lb/ft. (b) (16.1)(144) + (0.0750)(3) + (50.4)(2) Pa. P=2419 lb/ft; Pc=2419 + (2.00)(144) = 2707 lb/ft, or 18.80 lb/in?. %3D %3D 16.1 Ib /in? abs
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