2 %1E lI.U M 1:19homework parallel 2..11/1PROBLEMSDermne the unknown resistors of Fig. 6.72 given ther that R: = SR; and Ry = (1/2)R.Temine R, for the network of Fig. 6.73.240S120 A- 209 多R7= 10nR24FIG. 6.72Problem 6.FIG. 6.73Problem 7.SECTION E4 Parallel CircuiteIIIPI

if R1 , R2, R3 are in parallel , Rt is total resistance then 1Rt=1R1+1R2+1R3

PROBLEMS ene the unknown resistors of Fig. 6.72 given the the R- SR, and Ry - (1/2)R,. R, for the network of Fig. 6.73. R7= 10A R 2120 n 24 0 FIG. 6.72 Probiem 6. FIG. 6.73 Problem 7. TON E4 Paralel Circuite

PROBLEMS ene the unknown resistors of Fig. 6.72 given the the R- SR, and Ry - (1/2)R,. R, for the network of Fig. 6.73. R7= 10A R 2120 n 24 0 FIG. 6.72 Probiem 6. FIG. 6.73 Problem 7. TON E4 Paralel Circuite

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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Current Division Method

The generalized current divider formula is given by the following relation below,

Question

2 %1E lI.
U M 1:19
homework parallel 2..
11/1
PROBLEMS
Dermne the unknown resistors of Fig. 6.72 given the
r that R: = SR; and Ry = (1/2)R.
Temine R, for the network of Fig. 6.73.
240
S120 A
- 209 多
R7= 10n
R
24
FIG. 6.72
Problem 6.
FIG. 6.73
Problem 7.
SECTION E4 Parallel Circuite
II
IPI

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