Problems: 1. A stone is thrown near the surface of a planet and its horizontal and vertical position as a function of time are given as x(t) = 5+ 8t (horizontal) y(t) = 3+ 12t – 8t² (vertical) where x and y are given in meters and t is in seconds. Calculate the magnitude of surface gravitational acceleration of this Calculate the time when the stone is at its maximum height. Calculate the velocity vector at t-1.125s. Calculate the velocity vector when horizontal position of the stone planet in units of m/s. c) d) is 9m.

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Problems:
1. A stone is thrown near the surface of a planet and its horizontal and vertical position
as a function of time are given as
x(t) = 5 + 8t (horizontal)
y(t) = 3+ 12t – 8t2 (vertical)
where x and y are given in meters and t is in seconds.
a)
planet in units of mis.
by
c)
d)
is 9m.
Calculate the magnitude of surface gravitational acceleration of this
Calculate the time when the stone is at its maximum height.
Calculate the velocity vector at t=1.125s.
Calculate the velocity vector when horizontal position of the stone
Transcribed Image Text:Problems: 1. A stone is thrown near the surface of a planet and its horizontal and vertical position as a function of time are given as x(t) = 5 + 8t (horizontal) y(t) = 3+ 12t – 8t2 (vertical) where x and y are given in meters and t is in seconds. a) planet in units of mis. by c) d) is 9m. Calculate the magnitude of surface gravitational acceleration of this Calculate the time when the stone is at its maximum height. Calculate the velocity vector at t=1.125s. Calculate the velocity vector when horizontal position of the stone
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