Problema. Avem total: 296 monezi numarul monezitor: 1 kr = E 5Kr=F 10kr=T Ajutor: F= 4T F= E unde literele tunt numarul de monet A 1 Intrebare 1) care nr. de monezi este cel mai mare ? 2) cate moner de 1 Kr sunt in total ? 3) Suma totala de bani cu explicatie, ex Ex? + 1x? + Ex? = x... (tuma totala)
Problema. Avem total: 296 monezi numarul monezitor: 1 kr = E 5Kr=F 10kr=T Ajutor: F= 4T F= E unde literele tunt numarul de monet A 1 Intrebare 1) care nr. de monezi este cel mai mare ? 2) cate moner de 1 Kr sunt in total ? 3) Suma totala de bani cu explicatie, ex Ex? + 1x? + Ex? = x... (tuma totala)
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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![Problema.
Avem total: 296 monezi
numarul monezitor: 1 kr = E
5Kr=F 10kr=T
Ajutor: F= 4T
F=
E
unde literele tunt numarul de
monet
A
1
Intrebare
1) care nr. de monezi este cel mai mare ?
2) cate moner de 1 Kr sunt in total ?
3)
Suma totala de bani cu explicatie, ex
Ex? + 1x? + Ex? = x... (tuma totala)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F42dff072-7d42-411c-b912-034f8f72c397%2F11a0fbe7-d30e-48da-b6e7-ce5a900ab989%2Fystrx38_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Problema.
Avem total: 296 monezi
numarul monezitor: 1 kr = E
5Kr=F 10kr=T
Ajutor: F= 4T
F=
E
unde literele tunt numarul de
monet
A
1
Intrebare
1) care nr. de monezi este cel mai mare ?
2) cate moner de 1 Kr sunt in total ?
3)
Suma totala de bani cu explicatie, ex
Ex? + 1x? + Ex? = x... (tuma totala)
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