Problem_#09] Derive the SOP and POS expression for the truth table shown below.... ABCD X 0000 0 0001 0 0010 1 0011 0 0100 1 0101 1 0110 0 0111 1 1000 0 1001 0 1010 0 1011 1 1100 1 1101 0 1110 0 1111 1
Problem_#09] Derive the SOP and POS expression for the truth table shown below.... ABCD X 0000 0 0001 0 0010 1 0011 0 0100 1 0101 1 0110 0 0111 1 1000 0 1001 0 1010 0 1011 1 1100 1 1101 0 1110 0 1111 1
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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Computer Architecture Problem 9 help
![Problem_#09] Derive the SOP and POS expression for the truth table shown below...
ABCD X
0000 0
0001 0
0010 1
0011 0
0100 1
0101 1
0110 0
0111 1
1000 0
1001 0
1010 0
1011 1
1100 1
1101 0
1110 0
1111 1](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F913a0921-d398-48e9-845b-58c3dce12c9b%2F86d111a8-4d09-4cd6-9a2a-f1a70d75bf41%2Ffqvo7c9_processed.png&w=3840&q=75)
Transcribed Image Text:Problem_#09] Derive the SOP and POS expression for the truth table shown below...
ABCD X
0000 0
0001 0
0010 1
0011 0
0100 1
0101 1
0110 0
0111 1
1000 0
1001 0
1010 0
1011 1
1100 1
1101 0
1110 0
1111 1
Expert Solution
Step 1
GIVEN TRUTH TABLE
| A | B | C | D | X |
| 0 | 0 | 0 | 0 | 0 |
| 0 | 0 | 0 | 1 | 0 |
| 0 | 0 | 1 | 0 | 1 |
| 0 | 0 | 1 | 1 | 0 |
| 0 | 1 | 0 | 0 | 1 |
| 0 | 1 | 0 | 1 | 1 |
| 0 | 1 | 1 | 0 | 0 |
| 0 | 1 | 1 | 1 | 1 |
| 1 | 0 | 0 | 0 | 0 |
| 1 | 0 | 0 | 1 | 0 |
| 1 | 0 | 1 | 0 | 0 |
| 1 | 0 | 1 | 1 | 1 |
| 1 | 1 | 0 | 0 | 1 |
| 1 | 1 | 0 | 1 | 0 |
| 1 | 1 | 1 | 0 | 0 |
| 1 | 1 | 1 | 1 | 1 |
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