Problem_#06] Using the truth table below, develop a simplified SOP expression using a Karnaugh Map. Inputs Output ABC X 000 001 010 011 100 101 110 111 1 0 1

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
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Comp Architecture homework help 4

**Problem #06:** Using the truth table below, develop a simplified SOP expression using a Karnaugh Map.

**Truth Table:**

- **Inputs:** A, B, C
- **Output:** X

| A | B | C | X |
|---|---|---|---|
| 0 | 0 | 0 | 1 |
| 0 | 0 | 1 | 0 |
| 0 | 1 | 0 | 1 |
| 0 | 1 | 1 | 0 |
| 1 | 0 | 0 | 1 |
| 1 | 0 | 1 | 1 |
| 1 | 1 | 0 | 0 |
| 1 | 1 | 1 | 1 |

---

**Problem #07:** Use a Karnaugh Map to derive the simplified SOP expression for the truth table shown below.

**Truth Table:**

- **Inputs:** A, B, C, D
- **Output:** X

| A | B | C | D | X |
|---|---|---|---|---|
| 0 | 0 | 0 | 0 | 0 |
| 0 | 0 | 0 | 1 | 1 |
| 0 | 0 | 1 | 0 | 0 |
| 0 | 0 | 1 | 1 | 1 |
| 0 | 1 | 0 | 0 | 1 |
| 0 | 1 | 0 | 1 | 1 |
| 0 | 1 | 1 | 0 | 1 |
| 0 | 1 | 1 | 1 | 0 |
| 1 | 0 | 0 | 0 | 1 |
| 1 | 0 | 0 | 1 | 0 |
| 1 | 0 | 1 | 0 | 1 |
| 1 | 0 | 1 | 1 | 1 |
| 1 | 1 | 0 | 0 | 1 |
| 1 | 1 | 0 | 1 | 0 |
| 1 | 1 | 1 | 0 | 0 |
| 1 | 1 | 1 | 1 | 1 |

For both problems, use the Karnaugh Map method
Transcribed Image Text:**Problem #06:** Using the truth table below, develop a simplified SOP expression using a Karnaugh Map. **Truth Table:** - **Inputs:** A, B, C - **Output:** X | A | B | C | X | |---|---|---|---| | 0 | 0 | 0 | 1 | | 0 | 0 | 1 | 0 | | 0 | 1 | 0 | 1 | | 0 | 1 | 1 | 0 | | 1 | 0 | 0 | 1 | | 1 | 0 | 1 | 1 | | 1 | 1 | 0 | 0 | | 1 | 1 | 1 | 1 | --- **Problem #07:** Use a Karnaugh Map to derive the simplified SOP expression for the truth table shown below. **Truth Table:** - **Inputs:** A, B, C, D - **Output:** X | A | B | C | D | X | |---|---|---|---|---| | 0 | 0 | 0 | 0 | 0 | | 0 | 0 | 0 | 1 | 1 | | 0 | 0 | 1 | 0 | 0 | | 0 | 0 | 1 | 1 | 1 | | 0 | 1 | 0 | 0 | 1 | | 0 | 1 | 0 | 1 | 1 | | 0 | 1 | 1 | 0 | 1 | | 0 | 1 | 1 | 1 | 0 | | 1 | 0 | 0 | 0 | 1 | | 1 | 0 | 0 | 1 | 0 | | 1 | 0 | 1 | 0 | 1 | | 1 | 0 | 1 | 1 | 1 | | 1 | 1 | 0 | 0 | 1 | | 1 | 1 | 0 | 1 | 0 | | 1 | 1 | 1 | 0 | 0 | | 1 | 1 | 1 | 1 | 1 | For both problems, use the Karnaugh Map method
Expert Solution
Step 1

“Since you have asked multiple questions, we will solve the first question for you. If you want any specific question to be solved then please specify the question number or post only that question.” 

K-Map:

An alternative to using difficult theorems or manipulating equations is to utilize a visual tool called a Karnaugh map (K-map) to simplify the algebraic expressions of Boolean functions.

SOP expression :

The Sum of Product (SOP) expression results from adding the sum of two or more products (AND) (OR). In other words, the final AND-OR logical output is created by essentially ORing the outputs of two or more AND gates with the input of an OR gate.

 

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