Problem6.NE5.1 Compute a minimal realization for each of the following stateequations.1a. A =B =C = [1 1]-2-31b. A =1B =C = [5 4 1]-15-17-71c. A =1B =C = [3 1 0]-15-17-7111d. A =В —1-250-255-91-15C = [ 25 81 0]0 0 -250-1 0 0 -255ГО24e. A =1-91B =21-15C = [0 0 0 1]

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Answered: Problem6. NE5.1 Compute a minimal…

Advanced Engineering Mathematics

10th Edition

ISBN:9780470458365

Author:Erwin Kreyszig

Publisher:Erwin Kreyszig

Chapter2: Second-order Linear Odes

Section: Chapter Questions

Problem 1RQ

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1 3 Calculate (r+y)e drdy 0 2
2. LOQ Graphically solve each of the following. (a) 3x + y = 6 and x - y = 2 (b) x + 4y = -8 and 3x + 4y = 0 (c) 5x = 3y and y = -5 (d) 2x + 6y = 8 and x = -2 (e) y = 3x2 and y = 3 (f) y = -2x and x = 4 (g) x = -2 and 3x + 4y = 12 (h) y = -2 and 5x + 3y = 15
5. Write y 3(x- 5)(x-6) in standard form and graph y 3(x-5)(x-6) 3x-33x+90 c. y= a. y= 3x -11x+ 30 10 10 10 x io 10 x 10 40 b. y 3x-11x+ 30 d. y = 3x - 33x + 90 10 1:10 x
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1. Two well-mixed tanks are hooked up so that water with 2 pounds of salt per gallon flows into the first tank, well - mixed water flows out of the second tank, water flows from the first tank to the second tank, and water flows from the second tank to the first tank. All flows are constant. Determine how much water is in each of the two tanks, given if x is the amount of salt in the first tank and y is the amount of salt in the second tank then 3x = -x + y + 30 and 6y' 2x - 3y. The answer should be 45 gallons in the first tank and 30 gallons in the second tank. =

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Problem6. NE5.1 Compute a minimal realization for each of the following state equations. -[-2 a. A = b. A = -3 0 1 0 4-8 0 1 -15 -17 -7 0 c. A = - [8] C = [11] B = 1 1 -----0 -15 -17 -7 1 B = 1 C = [5 4 1] C = [310]