PROBLEM1 The result of the sieve analysis is shown below: a. What is percentage of the soil is retained in no.200 sieve? b. What is the effective grain size of the soil in mm? c. Determine the uniformity coefficient. Sieve no Diameter (mm) Mass retained grams 4 4.76 25 8 2.23 80 10 2.00 110 20 0.84 160 40 0.42 180 60 0.25 220 80 0.180 380 100 0.149 590 200 0.074 110 PAN 85

PROBLEM1 The result of the sieve analysis is shown below: a. What is percentage of the soil is retained in no.200 sieve? b. What is the effective grain size of the soil in mm? c. Determine the uniformity coefficient. Sieve no Diameter (mm) Mass retained grams 4 4.76 25 8 2.23 80 10 2.00 110 20 0.84 160 40 0.42 180 60 0.25 220 80 0.180 380 100 0.149 590 200 0.074 110 PAN 85

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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1. The following are the results of a sieve analysis U.S. Sieve No. 4 10 20 40 60 100 200 Pan Mass of Soil retained (g) 0 18.5 53.2 90.5 81.8 92.2 58.5 26.5 a) Determine the percent finer than each sieve and plot a grain-size distribution curve. b) Determine D10, D30, and Doo. c) Calculate the uniformity coefficient Cu d) Calculate the coefficient of gradation Ce
The results of the sieve analysis of soil A is tabulated below. Classify the soil according to AASHTO classification system and unified soil classification systems (USCS). Diameter (mm) 4.75 2.0 0.85 0.425 0.150 0.075 LL PL % Passing 100 93 85 80 55 50 18 70
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The following results were obtained by a mechanical sieve analysis. classify the soil using the Unified Soil Classification System. Sieve analysis % passing by weight is as follows: No.4 = 100% No. 40 = 96% No.200 = 52% Liquid Limit= 29 Plastic Limit = 11
Situation 3. Following are the results of a sieve analysis. Determine: a. Cu b. Cc c. So Sieve No. 4 6 10 20 40 60 100 200 Pan Diameter (mm) 4.760 2.380 2.000 0.840 0.420 0.250 0.149 0.074 Soil Sample Mass Retained (g) 100 180 86 160 105 134 110 65 45
Question 44 The given data shows a sieve analysis of a soil sample. Classify the soil using AASHTO Method. Tables are provided below. Sieve No. Diameter (mm) Percent Passing No. 4 No. 8 No. 10 No. 20 4.760 96 2.380 80 2.000 78 0.840 61 No. 40 0.420 56 No. 60 0.250 48 No. 100 0.150 39 No. 200 0.075 33 Characteristics of No. 40 Fraction LL 45 PL 36 General classification Granular materials (35% or less of total sample passing No. 200) A-I A-2 Group classification A-l-a A-1-5 A3 A-24 A-25 A-2-6 A-2-7 Sieve analysis (percent passing) No. 10 No. 40 No. 200 50 max. 30 max. 15 max. 50 max. 25 max. 51 min. 10 max. 35 max. 35 max. 35 max. 35 max. Characteristics of fraction passing No. 40 Liquid limit Plasticity index 40 max. 41 min. 40 max. 41 min. 6 max. NP 10 max. 10 max. 11 min. 11 min. Usual types of significant Stone fragments, gravel, and sand Fine Silty or clayey gravel and sand sand
Given below is the result of a sieve analysis done on a soil sample.Sieve No. Diameter Percent Passing %4 4.750 9510 2.000 8220 0.850 7340 0.425 5360 0.250 23100 0.150 14200 0.075 7Pan --- 0Determine the value of the coefficient of uniformity
The following results were obtained by a mechanical sieve analysis. classify the soil using the Unified Soil Classification System. Sieve analysis % passing by weight is as follows: No.4 = 100% No. 40 = 89% No.200 = 65% Liquid Limit= 44 Plastic Limit = 23
SG is 2.66 and temperature is 18 degrees celcius
Problem 4: The following are the results of a sieve analysis. a. Determine the percent finer than each sieve and plot a grain-size distribution curve. b. Determine D10, D30, D60, for the soil. c. Calculate the uniformity coefficient Cu. d. Calculate the coefficient of gradation Cc. U.S. Sieve N 4 10 20 40 60 100 200 Pan U.S. Sieve N Mass of Soil Retained (g) Problem 5: Repeat problem 4 with the following data. 4 6 10 20 40 60 100 200 Pan 0 18.5 53.2 90.5 81.8 92.2 58.5 26.5 Mass of Soil Retained (g) 0 0 0 9.1 249.4 179.8 22.7 15.5 23.5
The particle size characteristics of a soil are given in the table. Using USDA method, determine: Size (mm) Percent Finer 4.75 98 0.85 95 0.044 36 0.033 32 0.0062 19 0.0025 9. 0.0011 1. Percentage of gravel (in 4 decimal places) 2. Percentage of sand (in 4 decimal places) 3. Percentage of silt (in 4 decimal places) 4. Percentage of clay (in 4 decimal places)
2.8 2.7 The following are the results of a sieve and hydrometer analysis. Sieve number/ grain size Analysis Sieve Hydrometer Analysis Sieve 40 80 170 200 0.04 mm 0.02 mm 0.01 mm 0.005 mm 0.0015 mm Hydrometer Sieve number/ grain size Percent finer than a. Draw the grain-size distribution curve. b. Determine the percentages of gravel, sand, silt, and clay according to the MIT system. c. Repeat Part b according to the USDA system. d. Repeat Part b according to the AASHTO system. Repeat Problem 2.7 with the following data: 20 30 40 60 80 200 0.05 mm 0.03 mm 0.015 mm 0.006 mm 0.004 mm 0.0015 mm 100 96 85 80 59 39 26 15 8 Cengage Learning 2014 Percent finer than 100 96 90 76 65 34 27 19 11 7 6 5 Ⓒ Cengage Learning 2014