Problem. Consider the function f(x, y) = e-²-y? (a) Compute the tangent plane to the graph of f(x, y) at a the point (1, 2, e-5) (b) Compute the gradient of the function of three variables g(x, y, z) = f(x, y) – z at the point (1, 2, e-5) and show that every vector in the tangent plane in part (a) is perpendicular to this vector. (c) The above situation is part of a more general statement. Fill in the blanks to complete the geeral statement. Given any (differentiable) function f(x, y), the level surface g(x, y, z) = f(x, y) – - z = 0 can be identified with the f(r, y) as of the function. The gradient can be computed in terms of the partials of Vg = Since the gradient at a point (xo, yo, 2o) is always we see that Vg(xo, yo, zo) is perpendicular to the recovers the general equation of the tangent plane to the level surface passing through this point, of f at the point (ro, yo, f(ro, yo)). This 0 = Vg(x, y, z)· (x – xo, y - Yo, z - f(xo, yo))

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
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Chapter2: Second-order Linear Odes
Section: Chapter Questions
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Problem. Consider the function
f (x, y)
-x²-y?
= e
(a) Compute the tangent plane to the graph of f(x, y) at a the point (1, 2, e-5)
(b) Compute the gradient of the function of three variables
g(x, y, 2) = f(x, y) –
at the point (1, 2, e-5) and show that every vector in the tangent plane in part (a) is perpendicular to this
vector.
(c) The above situation is part of a more general statement. Fill in the blanks to complete the general statement.
Given any (differentiable) function f(x, y), the level surface
g(x, y, z) = f(x, y) – z = 0
can be identified with the
f (x, y) as
of the function. The gradient can be computed in terms of the partials of
Vg = (.
Since the gradient at a point (xo, Y0, 20) is always
we see that Vg(xo, Yo, 20) is perpendicular to the
recovers the general equation of the tangent plane
to the level surface passing through this point,
of f at the point (xo, Yo, f(xo, Yo)). This
0 = Vg(x, y, z) · (x – xo,y – Yo, z – f(xo, y0))
%3D
Transcribed Image Text:Problem. Consider the function f (x, y) -x²-y? = e (a) Compute the tangent plane to the graph of f(x, y) at a the point (1, 2, e-5) (b) Compute the gradient of the function of three variables g(x, y, 2) = f(x, y) – at the point (1, 2, e-5) and show that every vector in the tangent plane in part (a) is perpendicular to this vector. (c) The above situation is part of a more general statement. Fill in the blanks to complete the general statement. Given any (differentiable) function f(x, y), the level surface g(x, y, z) = f(x, y) – z = 0 can be identified with the f (x, y) as of the function. The gradient can be computed in terms of the partials of Vg = (. Since the gradient at a point (xo, Y0, 20) is always we see that Vg(xo, Yo, 20) is perpendicular to the recovers the general equation of the tangent plane to the level surface passing through this point, of f at the point (xo, Yo, f(xo, Yo)). This 0 = Vg(x, y, z) · (x – xo,y – Yo, z – f(xo, y0)) %3D
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