Problem to be solved and to be checked using Boyle's Law equation: In a J-shaped tube filled with mercury, initially, mercury levels in both limbs are the same. The initial volume of the trapped gas in the closed end is 0.50 L. The volume of the gas decreases to 0.30 L after the addition of mercury from the open end of the tube. Take note that the opened end of the tube is subjected to the atmosphere; thus, the initial pressure is equal to atmospheric pressure (1 atm = 780 mmHg). What will be the final pressure after the changes of the volume happened?

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Problem to be solved and to be checked using Boyle's Law equation:
In a J-shaped tube filled with mercury, initially, mercury levels in both limbs are the
same. The initial volume of the trapped gas in the closed end is 0.50 L. The
volume of the gas decreases to 0.30 L after the addition of mercury from the open
end of the tube. Take note that the opened end of the tube is subjected to the
atmosphere; thus, the initial pressure is equal to atmospheric pressure (1 atm =
780 mmHg). What will be the final pressure after the changes of the volume
happened?
Transcribed Image Text:Problem to be solved and to be checked using Boyle's Law equation: In a J-shaped tube filled with mercury, initially, mercury levels in both limbs are the same. The initial volume of the trapped gas in the closed end is 0.50 L. The volume of the gas decreases to 0.30 L after the addition of mercury from the open end of the tube. Take note that the opened end of the tube is subjected to the atmosphere; thus, the initial pressure is equal to atmospheric pressure (1 atm = 780 mmHg). What will be the final pressure after the changes of the volume happened?
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