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Problem: The Pugad Lawin-Ilocos Chapter members distributed food packs to the families who are infected with COVID-19 at Barangay 23, Laoag City. Each food pack contained rice, loaf of bread, biscuits and 3 in 1 instant coffee. They purchased 2 sacks of rice at PhP1 525.50 per sack, 50 loaves of bread at Php42.50 a loaf, 50 packs of biscuits at PhP48.50 each pack, 10 packs of 3-in-1 instant coffee at Php185.50 per pack. How much money was left from PhP10 000.00 after paying the items? Solution: The Polya's Method 1. Understand a. What is asked? b. What are the given facts? Money left after paying the items PHP10 000.00, 2 sacks of rice at PhP1 525.50 per sack, 50 loaves of bread at PhP42.50 a loaf, S0 packs of biscuits at PhP48.50 per pack, 10 packs of 3-in-1 instant coffee at Php185.50 per pack 2. Plan a. What operations are needed to solve Addition, Subtraction, and Multiplication the problem? b. What is the number sentence? PhP10 000.00-(2 x PHP1 525.50) + (50 x PhP42.50) + (50 x PhP48.50) + (10 x PhP185.50) =N 3.Solution a. Show the solution a. PhP1 525.50 PhP42.50 50 PHP3 051.00 PHP2 125.00 PhP48.50 PhP185.50 X 50 PhP2 425.00 X 10 PhP1 850.00 b. PhP3 051.00 c. PhP10 000.00 PhP2 125.00 -PhP 9 451.00 PhP2 425.00 PhP 549.00 • PhP1 850.00 PhP9 451.00 b. What is the answer? PhP549.00-money left after paying the items Php549.00 + (2 x PhP1 525.50)+ (50 x PhP42.50) + (50 x PhP48.50) + (10x PhP185.50) = PhP10 000.00 4. Check IDENTIFIED ERROR CORRECTION OF ERROR EXPLANATION OF CORRECTION

Problem: The Pugad Lawin-Ilocos Chapter members distributed food packs to the families who are infected with COVID-19 at Barangay 23, Laoag City. Each food pack contained rice, loaf of bread, biscuits and 3 in 1 instant coffee. They purchased 2 sacks of rice at PhP1 525.50 per sack, 50 loaves of bread at Php42.50 a loaf, 50 packs of biscuits at PhP48.50 each pack, 10 packs of 3-in-1 instant coffee at Php185.50 per pack. How much money was left from PhP10 000.00 after paying the items? Solution: The Polya's Method 1. Understand a. What is asked? b. What are the given facts? Money left after paying the items PHP10 000.00, 2 sacks of rice at PhP1 525.50 per sack, 50 loaves of bread at PhP42.50 a loaf, S0 packs of biscuits at PhP48.50 per pack, 10 packs of 3-in-1 instant coffee at Php185.50 per pack 2. Plan a. What operations are needed to solve Addition, Subtraction, and Multiplication the problem? b. What is the number sentence? PhP10 000.00-(2 x PHP1 525.50) + (50 x PhP42.50) + (50 x PhP48.50) + (10 x PhP185.50) =N 3.Solution a. Show the solution a. PhP1 525.50 PhP42.50 50 PHP3 051.00 PHP2 125.00 PhP48.50 PhP185.50 X 50 PhP2 425.00 X 10 PhP1 850.00 b. PhP3 051.00 c. PhP10 000.00 PhP2 125.00 -PhP 9 451.00 PhP2 425.00 PhP 549.00 • PhP1 850.00 PhP9 451.00 b. What is the answer? PhP549.00-money left after paying the items Php549.00 + (2 x PhP1 525.50)+ (50 x PhP42.50) + (50 x PhP48.50) + (10x PhP185.50) = PhP10 000.00 4. Check IDENTIFIED ERROR CORRECTION OF ERROR EXPLANATION OF CORRECTION

Algebra and Trigonometry (6th Edition)
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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Problem: The Pugad Lawin -llocos Chapter members distributed food packs to the families who are infected with COVID-19 at Barangay 23, Laoag City. Each food pack contained rice, loaf of bread, biscuits and 3 in 1 instant coffee. They purchased 2 sacks of rice at PhP1 525.50 per sack, 50 loaves of bread at Php42.50 a loaf, 50 packs of biscuits at PhP48.50 each pack, 10 packs of 3-in-1 instant coffee at Php185.50 per pack. How much money was left from PhP10 000.00 after paying the items? Solution: The Polya's Method 1. Understand a. What is asked? b. What are the given facts? Money left after paying the items PHP10 000.00, 2 sacks of rice at PhP1 525.50 per sack, 50 loaves of bread at PhP42.50 a loaf, 50 packs of biscuits at PHP48.50 per pack, 10 packs of 3-in-1 instant coffee at Php185.50 per pack 2. Plan a. What operations are needed to solve Addition, Subtraction, and Multiplication the problem? b. What is the number sentence? PHP10 000.00 - (2 x PHP1 525.50) + (50 x PHP42.50) + (50 x PHP48.50)+ (10 x PhP185.50) =N 3.Solution a. Show the solution a. PhP1 525.50 PhP42.50 50 PhP3 051.00 PhP2 125.00 PhP48.50 PhP185.50 50 PHP2 425.00 X 10 PhP1 850.00 b. PhP3 051.00 c. PhP10 000.00 - PhP 9 451.00 PhP 549.00 PHP2 125.00 PhP2 425.00 • PhP1 850.00 PhP9 451.00 b. What is the answer? PhP549.00-money left after paying the items Php549.00 + (2 x PhP1 525.50) + (50 x PhP42.50) + (50 x PhP48.50) + (10x PhP185.50) PhP10 000.00 4. Check IDENTIFIED ERROR CORRECTION OF ERROR EXPLANATION OF CORRECTION
Transcribed Image Text:Problem: The Pugad Lawin -llocos Chapter members distributed food packs to the families who are infected with COVID-19 at Barangay 23, Laoag City. Each food pack contained rice, loaf of bread, biscuits and 3 in 1 instant coffee. They purchased 2 sacks of rice at PhP1 525.50 per sack, 50 loaves of bread at Php42.50 a loaf, 50 packs of biscuits at PhP48.50 each pack, 10 packs of 3-in-1 instant coffee at Php185.50 per pack. How much money was left from PhP10 000.00 after paying the items? Solution: The Polya's Method 1. Understand a. What is asked? b. What are the given facts? Money left after paying the items PHP10 000.00, 2 sacks of rice at PhP1 525.50 per sack, 50 loaves of bread at PhP42.50 a loaf, 50 packs of biscuits at PHP48.50 per pack, 10 packs of 3-in-1 instant coffee at Php185.50 per pack 2. Plan a. What operations are needed to solve Addition, Subtraction, and Multiplication the problem? b. What is the number sentence? PHP10 000.00 - (2 x PHP1 525.50) + (50 x PHP42.50) + (50 x PHP48.50)+ (10 x PhP185.50) =N 3.Solution a. Show the solution a. PhP1 525.50 PhP42.50 50 PhP3 051.00 PhP2 125.00 PhP48.50 PhP185.50 50 PHP2 425.00 X 10 PhP1 850.00 b. PhP3 051.00 c. PhP10 000.00 - PhP 9 451.00 PhP 549.00 PHP2 125.00 PhP2 425.00 • PhP1 850.00 PhP9 451.00 b. What is the answer? PhP549.00-money left after paying the items Php549.00 + (2 x PhP1 525.50) + (50 x PhP42.50) + (50 x PhP48.50) + (10x PhP185.50) PhP10 000.00 4. Check IDENTIFIED ERROR CORRECTION OF ERROR EXPLANATION OF CORRECTION
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