PROBLEM: The molecular scenes below represent samples of four HA/A- buffers. (HA is RED and GREEN, A- is GREEN, and other ions and water are not shown.) Assume that the volume of the solutions (the samples) is the same. Sample 1 Sample 2 Sample 3 Sample 4 (a) Which buffer has the highest pH? (b) Which buffer has the greatest capacity? (c) Should we add a small amount of concentrated strong acid or strong base to convert sample 1 to sample 2 (assuming no volume changes)?

PROBLEM: The molecular scenes below represent samples of four HA/A- buffers. (HA is RED and GREEN, A- is GREEN, and other ions and water are not shown.) Assume that the volume of the solutions (the samples) is the same. Sample 1 Sample 2 Sample 3 Sample 4 (a) Which buffer has the highest pH? (b) Which buffer has the greatest capacity? (c) Should we add a small amount of concentrated strong acid or strong base to convert sample 1 to sample 2 (assuming no volume changes)?

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

PROBLEM: The molecular scenes below represent samples of four
HA/A- buffers. (HA is RED and GREEN, A- is GREEN, and
other ions and water are not shown.) Assume that the
volume of the solutions (the samples) is the same.
Sample 1
Sample 2
Sample 3
Sample 4
(a) Which buffer has the highest pH?
(b) Which buffer has the greatest capacity?
(c) Should we add a small amount of concentrated strong acid or
strong base to convert sample 1 to sample 2 (assuming no volume
changes)?

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a.) At what volume of added acid is the pH calculated by working an equilibrium problem based on the initial concentration and Kb of the weak base? b.) At what volume of added acid is the pH calculated by working an equilibrium problem based on the concentration and Ka of the conjugate acid?
Chemistry problem is seen in the attached image
Please solve.
I need help with part c I don’t know what to do.
Example Problem: Consider The Titration of 100.0 mL of 0.200 M CH3NH2 by 0.100 M HCl. Calculate The pH After 65.0 mL of HCI Added. (Kb for CH3NH2 = 4.4 x 10-4): a. 10.96. b. 9.75. c.7.00. d. 3.68. e. 2.54.
help please answer in text form with proper workings and explanation for each and every part and steps with concept and introduction no AI no copy paste remember answer must be in proper format with all working
Learning Goal: To understand how buffers use reserves of conjugate acid and conjugate base to counteract the effects of acid or base addition on pH. A buffer is a mixture of a conjugate acid-base pair In other words, it is a solution that contains a weak acid and its conjugate base, or a weak base and its conjugate acid. For example, an acetic acid buffer consists of acetic acid, CH₂COOH, and its conjugate base, the acetate ion CH,COO Because ions cannot simply be added to a solution, the conjugate base is added in a salt form (e.g. sodium acetate NaCH₂COO) Buffers work because the conjugate acid-base pair work together to neutralize the addition of Hor OH ions. Thus, for example, it Hions are added to the acetate buffer described above, they will be largely removed from solution by the reaction of H with the conjugate base: H+CH₂COO-CH₂COOH Similarly, any added OH ions will be neutralized by a reaction with the conjugate acid OH +CH₂COOH-CH₂COO+H₂O This butter system is described by…
Example Problem: Consider The Titration of 100.0 mL of 0.200 M CH3NH2 by 0.100 M HCl. Calculate The pH After 65.0 mL of HCl Added. (Kb for CH3NH2 = 4.4 x 10-4): a. 10.96. b. 9.75. c.7.00. d. 3.68. e. 2.54.
Solve correctly please. (Gpt/Ai wrong answer not allowed)
Give detailed Solution with explanation needed
p Please don't provide handwritting solution.
Example Problem: Consider The Titration of 100.0 mL of 0.200 M CH3NH2 by 0.100 M HCl. Calculate The pH After 65.0 mL of HCl Added. (Kb for CH3NH2 = 4.4 x 10-4): a. 10.96 b. 9.75 c. 7.00 d. 3.68 e. 2.54