ProblemThe graph below shows the spectrum ofsound that is produced by two pipessimultaneously vibrating with theirfundamental frequencies. Each pipe can beeither an open-open or an open-closed pipe.A200400f(Hz)Determine all possible lengths of the pipes.Support your answer with both mathematics,and explanation, and relevant diagrams.

Answered: Image /qna-images/answer/1797f92b-822f-4654-9cfd-258665fe46da.jpg

Answered: Problem The graph below shows the…

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Solve the problems with complete solution.State also the given and box the final answer 1. The speed of a longitudinal wave in silver, density 10.5 x 10^3 kg/m^3, is 2610 m/s. Compute Young’s Modulus for silver. 2. If the Young’s Modulus of a metal rod is 1.2 x 10^10 N/m^2 and the speed of sound in this rod is 1160 m/s, find its density.
SOLUTION (A) Find the first three harmonics at the given tension. Calculate the speed of the wave on the wire: Find the wire's fundamental frequency: Find the next two harmonics by multiplication: = V = f₁ Substitute the values of F, μ, and L. F 1/2 80 N (=) ¹/² = (2.00 x 10-³ kg/m = (B) Find the wavelength of the sound waves produced. Solve vs fλ for the wavelength and substitute the frequencies. F == A V f₁ 2L (C) Find the fundamental frequency corresponding to the elastic limit. Calculate the tension in the wire from the elastic limit: f₁ f₂ = 2f₁ = 2.00 × 10² Hz, ƒ3 = 3ƒ₁ = 3.00 × 10² Hz A₁ = v₁/f₁ = (345 m/s)/(1.00 x 10² Hz) = 3.45 m 1₂ = vs/f₂ = (345 m/s)/(2.00 x 10² Hz) = 1.73 m ^₂ = vs/f3 = (345 m/s)/(3.00 x 10² Hz) = 1.15 m = 2.00 × 10² m/s 2(1.00 m) elastic limit →→ F = (elastic limit) A F = (2.80 x 108 Pa) (2.56 × 10-7m²) = 71.7 N 1 V 2L F 1/2 -= 1.00 x 10² Hz μ = 2.00 x 10² m/s 1 2(1.00 m) 71.7 N 2.00 x 10-³ kg/m = 94.7 Hz
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Below is a figure representing two sources releasing sound waves. a. Label 1 point of constructive interference, and explain why this this point represents constructive interference. b. Label 1 point of destructive interference, and explain why this point represents destructive interference.
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Please provide details about your resolution process. Please show complete, organized and correct work for each question. Questions without complete and clear work will earn no points. You’re welcome to use your textbook and notes, but no calculators. One way to tune a piano is to strike a tuning fork (which emits only one specific frequency), then immediately strike the piano key for the frequency being sounded by the fork, and listen for beats. If the frequency of an out-of-tune A4string is 420.0 Hz, and a tuner strikes an A4 tuning fork (frequency 440.0 Hz),a. …what beat frequency will the tuner hear?a) ????? = _____________________b. …and what frequency note will the tuner hear?b) ????? = _____________________
Two identical point sources are generating waves with the same frequency and amplitude. The two sources are in phase with each other, so the two sources generate wave crests at the same instant. The wavelength of the waves is equal to the distance between the two sources. A. List all the labeled points where the waves from the two sources constructively interfere. If there are no such points, indicate that by stating "none". Separate each letter with a space. Hint: Determine the difference in the distance that each wave travels from the point sources. For example the difference between the distance travelled to B = 1.5λ - 0.5λ. Constructive interference occurs at ΔL=nλ. Destructive occurs at ΔL=nλ/2. B. List all the labeled points where the waves from the two sources destructively interfere. If there are no such points, indicate that by stating "none". Separate each letter with a space. Hint: Constructive occurs at ΔL=nλ. Destructive occurs at L=ΔL=nλ/2.
Learning Goal: To understand standing waves, including calculation of X and f, and to learn the physical meaning behind some musical terms. The columns in the figure (Figure 1) show the instantaneous shape of a vibrating guitar string drawn every 1 ms. The guitar string is 60 cm long. The left column shows the guitar string shape as a sinusoidal traveling wave passes through it. Notice that the shape is sinusoidal at all times and specific features, such as the crest indicated with the arrow, travel along the string to the right at a constant speed. The right column shows snapshots of the sinusoidal standing wave formed when this sinusoidal traveling wave passes through an identically shaped wave moving in the opposite direction on the same guitar string. The string is momentarily flat when the underlying traveling waves are exactly out of phase. The shape is sinusoidal with twice the original amplitude when the underlying waves are momentarily in nhaco Thic nattern is called a…
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m/public/activity/6004002/assessment Google Redirecting... G. M Mail G Images M Wrie Zearn Math: A Com. 1 6.4.2 Teat (CST): Waves Question 1 of 13 A student rings a brass bell with a frequency of 100 Hz. The sound wave travels through brass, air, and glass. What is the wavelength of the wave in brass? Wave speed (m/s) Medium Brass 4,700 Air 346 Glass 5,640 A. 47 m B. 4.7 m C. 0.021 m D. 0.21 m PREVIOUS

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