ProblemThe graph below shows the spectrum ofsound that is produced by two pipessimultaneously vibrating with theirfundamental frequencies. Each pipe can beeither an open-open or an open-closed pipe.A200400f(Hz)Determine all possible lengths of the pipes.Support your answer with both mathematics,and explanation, and relevant diagrams.

Answered: Image /qna-images/answer/1797f92b-822f-4654-9cfd-258665fe46da.jpg

Answered: Problem The graph below shows the…

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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View Policies Current Attempt in Progress In the figure, S is a small loudspeaker driven by an audio oscillator and amplifier, adjustable in frequency from 1100 to 2100 Hz only. Tube D is a piece of cylindrical sheet-metal pipe 53.9 cm long and open at both ends. (a) If the speed of sound in air is 344 m/s at the existing temperature, at how many frequencies will a resonance occur in the pipe when the frequency emitted by the speaker is varied from 1100 Hz to 2100 Hz? (b) What is the lowest resonant frequency in the given interval? (a) Number (b) Number C Units Units D <
Solve the problems with complete solution.State also the given and box the final answer 1. The speed of a longitudinal wave in silver, density 10.5 x 10^3 kg/m^3, is 2610 m/s. Compute Young’s Modulus for silver. 2. If the Young’s Modulus of a metal rod is 1.2 x 10^10 N/m^2 and the speed of sound in this rod is 1160 m/s, find its density.
SOLUTION (A) Find the first three harmonics at the given tension. Calculate the speed of the wave on the wire: Find the wire's fundamental frequency: Find the next two harmonics by multiplication: = V = f₁ Substitute the values of F, μ, and L. F 1/2 80 N (=) ¹/² = (2.00 x 10-³ kg/m = (B) Find the wavelength of the sound waves produced. Solve vs fλ for the wavelength and substitute the frequencies. F == A V f₁ 2L (C) Find the fundamental frequency corresponding to the elastic limit. Calculate the tension in the wire from the elastic limit: f₁ f₂ = 2f₁ = 2.00 × 10² Hz, ƒ3 = 3ƒ₁ = 3.00 × 10² Hz A₁ = v₁/f₁ = (345 m/s)/(1.00 x 10² Hz) = 3.45 m 1₂ = vs/f₂ = (345 m/s)/(2.00 x 10² Hz) = 1.73 m ^₂ = vs/f3 = (345 m/s)/(3.00 x 10² Hz) = 1.15 m = 2.00 × 10² m/s 2(1.00 m) elastic limit →→ F = (elastic limit) A F = (2.80 x 108 Pa) (2.56 × 10-7m²) = 71.7 N 1 V 2L F 1/2 -= 1.00 x 10² Hz μ = 2.00 x 10² m/s 1 2(1.00 m) 71.7 N 2.00 x 10-³ kg/m = 94.7 Hz
Find amplitude , wavelength frequency and velocity of wave?
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Below is a figure representing two sources releasing sound waves. a. Label 1 point of constructive interference, and explain why this this point represents constructive interference. b. Label 1 point of destructive interference, and explain why this point represents destructive interference.
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Please provide details about your resolution process. Please show complete, organized and correct work for each question. Questions without complete and clear work will earn no points. You’re welcome to use your textbook and notes, but no calculators. One way to tune a piano is to strike a tuning fork (which emits only one specific frequency), then immediately strike the piano key for the frequency being sounded by the fork, and listen for beats. If the frequency of an out-of-tune A4string is 420.0 Hz, and a tuner strikes an A4 tuning fork (frequency 440.0 Hz),a. …what beat frequency will the tuner hear?a) ????? = _____________________b. …and what frequency note will the tuner hear?b) ????? = _____________________
Learning Goal: To understand standing waves, including calculation of X and f, and to learn the physical meaning behind some musical terms. The columns in the figure (Figure 1) show the instantaneous shape of a vibrating guitar string drawn every 1 ms. The guitar string is 60 cm long. The left column shows the guitar string shape as a sinusoidal traveling wave passes through it. Notice that the shape is sinusoidal at all times and specific features, such as the crest indicated with the arrow, travel along the string to the right at a constant speed. The right column shows snapshots of the sinusoidal standing wave formed when this sinusoidal traveling wave passes through an identically shaped wave moving in the opposite direction on the same guitar string. The string is momentarily flat when the underlying traveling waves are exactly out of phase. The shape is sinusoidal with twice the original amplitude when the underlying waves are momentarily in nhaco Thic nattern is called a…
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Data Table 1 Trial No. f (Hz)2 egment ength 33.3 5 33.S Data Analysis 1. Plot a graph of Frequency squared vs. Segments square 2. Determine the slope of the best-fit line on the Frequency squared vs. n2 graph. 3. Using the slope, length, and frequency, calculate the linear mass density of the string. (Hint: The slope is equal to). Solve for the linear mass density Calculate the percent difference between this value and the directly measured value and record it in the Lab Report, Table 3 4. Part 2: Variable Tension- keeping frequency and length constant In this variation, the mass per unit length, μ, the vibrating length, L are fixed. The tension, T, is varied to produce the normal modes of vibration. One must obtain a series of anti-nodes, n, by changing the tension on the string. It may not be possible to obtain the fundamental frequency. The mass may be too high for the driver to move the string. We can take our basic equation and solve for the tension. (12) 7125 kil A plot of T…

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