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Problem Statement The area under a curve can be estimated by breaking the x axis into increments, evaluating the function at a point inside that increment, and approximating the area under the curve in that increment as a rectangle. The figure below shows this approximation with an increment of 1 and the function being evaluated at the midpoint of the increment.

Problem Statement The area under a curve can be estimated by breaking the x axis into increments, evaluating the function at a point inside that increment, and approximating the area under the curve in that increment as a rectangle. The figure below shows this approximation with an increment of 1 and the function being evaluated at the midpoint of the increment.

Computer Networking: A Top-Down Approach (7th Edition)
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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Problem Statement The area under a curve can be estimated by breaking the x axis into increments, evaluating the function at a point inside that increment, and approximating the area under the curve in that increment as a rectangle. The figure below shows this approximation with an increment of 1 and the function being evaluated at the midpoint of the increment. 20 18 16 14 12 > 10 6 4 2 0.5 1 1.5 2.5 3 3.5 4 Given a range (upper and lower limits) and increment, use the midpoint approximation as shown above to estimate the area under the curve: x² + 2* y = In (x) You can assume that the increment given will evenly divide the range. Variable List % Inputs % Xmin the minimum limit of the range the maximum limit of the range % Xmax % inc the increment for the numerical approximation % Outputs % area the final approximation of the area under the curve for the given range nmand Window UTF-8
Transcribed Image Text:Problem Statement The area under a curve can be estimated by breaking the x axis into increments, evaluating the function at a point inside that increment, and approximating the area under the curve in that increment as a rectangle. The figure below shows this approximation with an increment of 1 and the function being evaluated at the midpoint of the increment. 20 18 16 14 12 > 10 6 4 2 0.5 1 1.5 2.5 3 3.5 4 Given a range (upper and lower limits) and increment, use the midpoint approximation as shown above to estimate the area under the curve: x² + 2* y = In (x) You can assume that the increment given will evenly divide the range. Variable List % Inputs % Xmin the minimum limit of the range the maximum limit of the range % Xmax % inc the increment for the numerical approximation % Outputs % area the final approximation of the area under the curve for the given range nmand Window UTF-8
Inputs This section is only needed when running the code in MATLAB. MATLAB Grader automatically creates these variables. % Test Case 1 Xmin 2; 10; Xmax %3B % Test case output: inc = % area = 823.4722 % % Test Case 2 % Xmin 2; % Xmax = 10; 0.01; % % Test case output: % inc = % % area = 870.0278 % % Test Case 3 % Xmin = 3; % Xmax % inc % % Test case output: 8; 0.5; % % area = 282.6901 Program
Transcribed Image Text:Inputs This section is only needed when running the code in MATLAB. MATLAB Grader automatically creates these variables. % Test Case 1 Xmin 2; 10; Xmax %3B % Test case output: inc = % area = 823.4722 % % Test Case 2 % Xmin 2; % Xmax = 10; 0.01; % % Test case output: % inc = % % area = 870.0278 % % Test Case 3 % Xmin = 3; % Xmax % inc % % Test case output: 8; 0.5; % % area = 282.6901 Program
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