Problem: Oscillator P m A string, tied to a sinusoidal oscillator at P and running over a support at Q, is stretched by a block of mass m. The separation L between P and Q is 1.20 m, and the frequency f of the oscillator is fixed at 120 Hz. The amplitude of the motion at P is small enough for that point to be considered a node. A node also exists at Q. A standing wave appears when the mass of the hanging block is 286.1 g or 447.0 g, but not for any intermediate mass. √, where T is the tension in V We will see in Lecture 4 that the wave speed along a uniform string is v = the string, and u is the linear mass density. What is the linear mass density of the string?
Problem: Oscillator P m A string, tied to a sinusoidal oscillator at P and running over a support at Q, is stretched by a block of mass m. The separation L between P and Q is 1.20 m, and the frequency f of the oscillator is fixed at 120 Hz. The amplitude of the motion at P is small enough for that point to be considered a node. A node also exists at Q. A standing wave appears when the mass of the hanging block is 286.1 g or 447.0 g, but not for any intermediate mass. √, where T is the tension in V We will see in Lecture 4 that the wave speed along a uniform string is v = the string, and u is the linear mass density. What is the linear mass density of the string?
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Transcribed Image Text:Problem:
Oscillator P
m
A string, tied to a sinusoidal oscillator at P and running over a support at Q, is stretched by a block of
mass m. The separation L between P and Q is 1.20 m, and the frequency f of the oscillator is fixed at 120
Hz.The amplitude of the motion at P is small enough for that point to be considered a node. A node also
exists at Q. A standing wave appears when the mass of the hanging block is 286.1 g or 447.0 g, but not for
any intermediate mass.
We will see in Lecture 4 that the wave speed along a uniform string is v= √, where T is the tension in
the string, and is the linear mass density. What is the linear mass density of the string?
μl
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