Problem MCD = Greatest common divisor (GCD) t them.a, b, c and m €Zsuch that m 22. a-). Prove that a = b (mod m), then MCD(a, m) = MC D(b, m). b-1 Show that ac = bc (mod m), then a= b (mod m MCD(c,m)

Advanced Engineering Mathematics
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ISBN:9780470458365
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Chapter2: Second-order Linear Odes
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MCD = Greatest common divisor (GCD)
Let them.a, b, c and m eZsuch that m 2 2.
a-). Prove that a = b (mod m), then MCD(a, m) = MCD(b, m).
b-). Show that ac = bc (mod m), then a = b (mod
MCD(c,m))
Transcribed Image Text:Problem MCD = Greatest common divisor (GCD) Let them.a, b, c and m eZsuch that m 2 2. a-). Prove that a = b (mod m), then MCD(a, m) = MCD(b, m). b-). Show that ac = bc (mod m), then a = b (mod MCD(c,m))
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