Problem II Find the inverse of the following matrix. 1 1 1 1 1 1 1 1 2 1 0-10 2 100 -1 20 21. 25. 29. 33. 37. 1 0 1 0 1 1 1 1 100 1 020 -1 02 2 1 1 2 1 1 2 1 0011 0 2 1 1 0 0 12 10 0 1 2 1 00 2 1 1 3 0 1001 1002 -1 250 22. 26. 30. 34. 38. 1 100 -1 1 1 1 1 1 1 0 1 0 0 000 2 1 1 2) 1 2 1 1 1 1 0 0 2100 2 1 0 1 210 0121 0 0 1 1 013 1 00 1 10 0 2 0 25 -1 23. 27. 31. 35. 39. 1 1 1 0-12 0 1 0 100 -1 2 1 1000 1 1 0 0 1 1 1 0 1 1 1 2 1 0 0 1 1 0 0 1 2 1 1 2 112 001 0 1 2 1 1210 2100 011 -1 100 3 200 5 0 12 -1 24. 28. 32. 36. 40. 1 1 1 100 -1 0 0 2 0 -1 1 2 0 0 0 1 0011 0 1 1 1 1 1 0 0 1 2 0011 1 1 2 1 2 112 0 0 1 2 0 1 2 1 1 2 1 0 1100 -1 1 1 0 100 3 2005 -1 1 2 0
Problem II Find the inverse of the following matrix. 1 1 1 1 1 1 1 1 2 1 0-10 2 100 -1 20 21. 25. 29. 33. 37. 1 0 1 0 1 1 1 1 100 1 020 -1 02 2 1 1 2 1 1 2 1 0011 0 2 1 1 0 0 12 10 0 1 2 1 00 2 1 1 3 0 1001 1002 -1 250 22. 26. 30. 34. 38. 1 100 -1 1 1 1 1 1 1 0 1 0 0 000 2 1 1 2) 1 2 1 1 1 1 0 0 2100 2 1 0 1 210 0121 0 0 1 1 013 1 00 1 10 0 2 0 25 -1 23. 27. 31. 35. 39. 1 1 1 0-12 0 1 0 100 -1 2 1 1000 1 1 0 0 1 1 1 0 1 1 1 2 1 0 0 1 1 0 0 1 2 1 1 2 112 001 0 1 2 1 1210 2100 011 -1 100 3 200 5 0 12 -1 24. 28. 32. 36. 40. 1 1 1 100 -1 0 0 2 0 -1 1 2 0 0 0 1 0011 0 1 1 1 1 1 0 0 1 2 0011 1 1 2 1 2 112 0 0 1 2 0 1 2 1 1 2 1 0 1100 -1 1 1 0 100 3 2005 -1 1 2 0
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
Related questions
Question
Parts 85-88 Using elementary row operations please
Transcribed Image Text:Problem II Find the inverse of the following matrix.
1 1 1 1
1 1 1
1
0
0-1 21
1 100
0-1 02
100
1
0
-1 2 0
1 2
0
21.
25.
29.
33.
37.
1 1 1
100
020 -1
021 -1
1
2 1 1 2
1 12 1
0011
0012
1 1 0 0
1210
0121
00 2
−1 1 3 0
1 001
1002
250
22.
26.
30.
34.
38.
1 1 1
110
100
1000
2
1 1 2
1 2 1 1
1 1 0 0
2100
2 1 0 0
12 10
0121
0 01 1
013
100 1
100 2
025-1
23.
27.
31.
35.
39.
1 1 1
-1 2 0
100
-1 2 1
100
1 100
1 1 1 0
1 1 1
2 1 0
1 100
1 2 1 1
2 1 1 2
0 0 1 1
0121
1210
2100
0 1 1
100 3
200 5
012 −1
24.
28.
32.
36.
40.
1
1
0
0
1 1 1
100
-1 0 2
-1 1 2
0001
0 0 1
1
0 1 1
1
1 1 1 1
0 0 1
0 0 1
1 1 2
2 112
2)
1
1
0 0 1 2)
0121
1210
1 00
-1 1 1 0
1003
2005
-1 1 2 0
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