Problem: If n is a positive integer, then n factorial (written n!) is the product of the numbers from 1 through n. Write a recursive function to calculate n factorial. Hints: n! =n · (n – 1) · (n – 2) 3. 2· 1 As written, n! can be calculated iteratively with a for loop-however, when rewritten as n! = n · ((n – 1) · (n – 2) · 3 2 . 1) = n · (n – 1)! ... n! is expressed in terms of (n – 1)! and can be calculated recursively with n =1 as the base case.
Problem: If n is a positive integer, then n factorial (written n!) is the product of the numbers from 1 through n. Write a recursive function to calculate n factorial. Hints: n! =n · (n – 1) · (n – 2) 3. 2· 1 As written, n! can be calculated iteratively with a for loop-however, when rewritten as n! = n · ((n – 1) · (n – 2) · 3 2 . 1) = n · (n – 1)! ... n! is expressed in terms of (n – 1)! and can be calculated recursively with n =1 as the base case.
C++ Programming: From Problem Analysis to Program Design
8th Edition
ISBN:9781337102087
Author:D. S. Malik
Publisher:D. S. Malik
Chapter15: Recursion
Section: Chapter Questions
Problem 6PE
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Question
![Submission: Submit python code
Problem: If n is a positive integer, then n factorial (written n!) is the product of the numbers from
1 through n. Write a recursive function to calculate n factorial.
Hints:
n! =
(n – 1) · (n– 2)
2: 1
As written, n! can be calculated iteratively with a for loop-however, when rewritten as
n! = n · ((n – 1) · (n – 2)
3 · 2 · 1) = n · (n – 1)!
n! is expressed in terms of (n – 1)! and can be calculated recursively with n = 1 as the base case.
|
Example input and output:
>>> factorial(5)
120
>>>](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F09fcf446-1afb-4b15-acb5-39347ac88924%2F9ddc5381-71b6-4f3c-ba4a-583b1ab4395e%2Fxzbck6v_processed.png&w=3840&q=75)
Transcribed Image Text:Submission: Submit python code
Problem: If n is a positive integer, then n factorial (written n!) is the product of the numbers from
1 through n. Write a recursive function to calculate n factorial.
Hints:
n! =
(n – 1) · (n– 2)
2: 1
As written, n! can be calculated iteratively with a for loop-however, when rewritten as
n! = n · ((n – 1) · (n – 2)
3 · 2 · 1) = n · (n – 1)!
n! is expressed in terms of (n – 1)! and can be calculated recursively with n = 1 as the base case.
|
Example input and output:
>>> factorial(5)
120
>>>
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