Problem Description Use this project to write and run a C program that performs the following: O Creates 6-element 1-D integer array named Numbers. O O O O O O Fill the array with random values between (2 and 12), each run should give new random values. and prints them in tabular format as in the sample output Pass the array to a function called findHighest that finds the maximum number in the array recursively and return it to the main. (don't use predefined functions to find the max) Pass the array to function called find Lowest that finds the minimum number in the array I recursively and return it to the main. (don't use predefined functions to find the min) Pass the max and min numbers to a recursive function called findGCD that finds the Greatest Common Divisor (GCD) and return it to the main. Note: Greatest Common Divisor (GCD) for two positive integers a and b is the largest number d such that a/d and b/d doesn't have any remainder. For example GCD(63) 3 and GCD(6 10) = 2 Pass the max and min numbers to a recursive function called intDivision, which finds and returns the result of dividing the max with the min. The main function Prints the values of the maximum, minimum the GCD and the division in tabular form as shown in the sample output.

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
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Problem Description
Use this project to write and run a C program that performs the following:
O Creates 6-element 1-D integer array named Numbers.
O
O
O
O
O
Fill the array with random values between (2 and 12), each run should give new random values
and prints them in tabular format as in the sample output
O
Pass the array to a function called findHighest that finds the maximum number in the array
recursively and return it to the main. (don't use predefined functions to find the max)
Pass the array to function called find Lowest that finds the minimum number in the array
I
recursively and return it to the main. (don't use predefined functions to find the min)
Pass the max and min numbers to a recursive function called intDivision, which finds and
returns the result of dividing the max with the min.
The main function Prints the values of the maximum, minimum the GCD and the division in
tabular form as shown in the sample output.
Sample Output
Pass the max and min numbers to a recursive function called findGCD that finds the Greatest
Common Divisor (GCD) and return it to the main.
Note: Greatest Common Divisor (GCD) for two positive integers a and b is the largest
number d such that a/d and b / d doesn't have any remainder.
For example
GCD(63) 3 and GCD(6 10) = 2
W
Transcribed Image Text:Problem Description Use this project to write and run a C program that performs the following: O Creates 6-element 1-D integer array named Numbers. O O O O O Fill the array with random values between (2 and 12), each run should give new random values and prints them in tabular format as in the sample output O Pass the array to a function called findHighest that finds the maximum number in the array recursively and return it to the main. (don't use predefined functions to find the max) Pass the array to function called find Lowest that finds the minimum number in the array I recursively and return it to the main. (don't use predefined functions to find the min) Pass the max and min numbers to a recursive function called intDivision, which finds and returns the result of dividing the max with the min. The main function Prints the values of the maximum, minimum the GCD and the division in tabular form as shown in the sample output. Sample Output Pass the max and min numbers to a recursive function called findGCD that finds the Greatest Common Divisor (GCD) and return it to the main. Note: Greatest Common Divisor (GCD) for two positive integers a and b is the largest number d such that a/d and b / d doesn't have any remainder. For example GCD(63) 3 and GCD(6 10) = 2 W
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