Problem A rod of length e has a uniform charge density A and a total charge Q. Ca the electric field at a point P along the axi the rod, a distance a from one end (Fig. 2 Strategy Choose a small element of the distribution, such as the blue section mar the diagram. Find the electric field due to segment, then sum up all of the segment

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Example 23.7 The Electric Field Due to a Charged Rod
Problem A rod of length e has a uniform linear
charge density d and a total charge Q. Calculate
the electric field at a point P along the axis of
the rod, a distance a from one end (Fig. 23.17).
dq = A dx
Strategy Choose a small element of the charge
distribution, such as the blue section marked in
the diagram. Find the electric field due to the
segment, then sum up all of the segments'
vector contributions to the overall field at a
point P along the axis of the rod.
P
Figure 23.17 The electric field at P due to a uniformly
charged rod lying along the x axis. The field at P due to
the segment of charge dg is kedg/x2. The total field at P
is the vector sum over all segments of the rod.
Transcribed Image Text:Example 23.7 The Electric Field Due to a Charged Rod Problem A rod of length e has a uniform linear charge density d and a total charge Q. Calculate the electric field at a point P along the axis of the rod, a distance a from one end (Fig. 23.17). dq = A dx Strategy Choose a small element of the charge distribution, such as the blue section marked in the diagram. Find the electric field due to the segment, then sum up all of the segments' vector contributions to the overall field at a point P along the axis of the rod. P Figure 23.17 The electric field at P due to a uniformly charged rod lying along the x axis. The field at P due to the segment of charge dg is kedg/x2. The total field at P is the vector sum over all segments of the rod.
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