Problem A block of mass m is placed on a rough surface inclined relative to the horizontal. The incline angle is increased until the block start to move. Show that you can obtain the coefficient of static friction Hs by measuring the critical angle 8 where slipping occurs. mg pinto Solution

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A block of mass m is placed on a rough surface inclined relative to the horizontal. The incline angle is increased
until the block start to move. Show that you can obtain the coefficient of static friction by measuring the critical angle where slipping occurs.

Write powers or subscript as is. Ex: Use b2 if you mean
b2
or b2
Write transcendental functions as is. Ex. Use costheta if you mean cose.
Spell out Greek letters. Ex: Use pi if you mean A
Write answers without spaces. Ex: Use 2epsilonOr3 if you mean 2ɛ r³.
Write fractions with a slash. Ex: Use 1/2 if you mean
Transcribed Image Text:Write powers or subscript as is. Ex: Use b2 if you mean b2 or b2 Write transcendental functions as is. Ex. Use costheta if you mean cose. Spell out Greek letters. Ex: Use pi if you mean A Write answers without spaces. Ex: Use 2epsilonOr3 if you mean 2ɛ r³. Write fractions with a slash. Ex: Use 1/2 if you mean
Problem
A block of mass m is placed on a rough surface inclined relative to the horizontal. The incline angle is increased
until the block start to move. Show that you can obtain the coefficient of static friction ps by measuring the critical
angle e where slipping occurs.
Solution
Just before slipping, we say that the block is still at rest, so the net force on the x-axis is:
EFx=mg|
Evaluating, we get:
= mg|
But the frictional force is expressed as the product of coefficient and the normal force so.
Hs
= mg
For an inclined plane. The normal force is
n=mg
Then,
Hs=mg
cos(e)
so:
Hs=
tan(e)
Transcribed Image Text:Problem A block of mass m is placed on a rough surface inclined relative to the horizontal. The incline angle is increased until the block start to move. Show that you can obtain the coefficient of static friction ps by measuring the critical angle e where slipping occurs. Solution Just before slipping, we say that the block is still at rest, so the net force on the x-axis is: EFx=mg| Evaluating, we get: = mg| But the frictional force is expressed as the product of coefficient and the normal force so. Hs = mg For an inclined plane. The normal force is n=mg Then, Hs=mg cos(e) so: Hs= tan(e)
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