Problem: A 3.75 g sample of calcium carbonate was dissolved using 6 m hcl and diluted with water to 500 ml. a 50.00 ml portion of this solution is transferred to a flask and the ph was adjusted by adding 5ml of NH3-NH4Cl buffer. after adding EBT indicator, the solution required 47 ml EDTA to reach the end point. given: CaCO3 = 3.75g HCl Conc = 6M Water = 500 mL or 0.5 L EDTA = 47 mL QUESTION: 1. What is the weight (in grams) to be used? 2. What is the molecular weight to be used?
Problem: A 3.75 g sample of calcium carbonate was dissolved using 6 m hcl and diluted with water to 500 ml. a 50.00 ml portion of this solution is transferred to a flask and the ph was adjusted by adding 5ml of NH3-NH4Cl buffer. after adding EBT indicator, the solution required 47 ml EDTA to reach the end point. given: CaCO3 = 3.75g HCl Conc = 6M Water = 500 mL or 0.5 L EDTA = 47 mL QUESTION: 1. What is the weight (in grams) to be used? 2. What is the molecular weight to be used?
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Problem:
A 3.75 g sample of calcium carbonate was dissolved using 6 m hcl and diluted with water to 500 ml. a 50.00 ml portion of this solution is transferred to a flask and the ph was adjusted by adding 5ml of NH3-NH4Cl buffer. after adding EBT indicator, the solution required 47 ml EDTA to reach the end point.
given:
CaCO3 = 3.75g
HCl Conc = 6M
Water = 500 mL or 0.5 L
EDTA = 47 mL
QUESTION:
1. What is the weight (in grams) to be used?
2. What is the molecular weight to be used?
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