OCAML Problem ### Problem 8We have seen the benefits of the 'fold' function for list data structures. In a similar fashion, write a function:```ocamlfold_inorder : ('a -> 'b -> 'a) -> 'a -> 'b tree -> 'a```That does an inorder fold of the tree. The function should traverse the left subtree, visit the root, and then traverse the right subtree. For example,```ocamlfold_inorder (fun acc x -> acc @ [x]) [] (Node (Node (Leaf, 1, Leaf), 2, Node (Leaf, 3, Leaf))) = [1; 2; 3]``````ocamllet rec fold_inorder f acc t = (* YOUR CODE HERE *)``````ocamlassert (fold_inorder (fun acc x -> acc @ [x]) [] (Node (Node (Leaf, 1, Leaf), 2, Node (Leaf, 3, Leaf))) = [1; 2; 3]);assert (fold_inorder (fun acc x -> acc + x) 0 (Node (Node (Leaf, 1, Leaf), 2, Node (Leaf, 3, Leaf))) = 6)```### ExplanationThis problem involves implementing a higher-order function `fold_inorder` that performs an inorder traversal on a binary tree data structure. The function uses a fold operation, commonly employed to accumulate results across data structures like lists or trees. The snippet provides an OCaml function definition and two test assertions:1. **Function Definition:** - `fold_inorder` function takes three parameters: - A function `f` of type `('a -> 'b -> 'a)`. - An accumulator `acc` of type `'a`. - A binary tree `t` of type `'b tree`. - It recursively traverses the tree, applying the function `f` to accumulate a result using the inorder traversal pattern (left subtree, root, right subtree).2. **Assertions:** - The first assertion applies `fold_inorder` with a function that appends each tree element to an accumulator list, producing the list `[1; 2; 3]` from the given tree. - The second assertion sums the values of the tree nodes, resulting in a total of `6`.### Diagram DescriptionThere

Given: The working of fold function To Compute: Implement a function that does inorder traversal of…

Problem 8 We have seen the benefits of the 'fold' function for list data structures. In a similar fashion, write a function In [ ]: fold_inorder : 'a > 'b> 'a) -> 'a -> 'b tree -> 'a That does an inorder fold of the tree. The function should traverse the left subtree, visit the root, and then traverse the right subtree. For example, fold_inorder (fun acc x -> acc @ [x]) [] (Node (Node (Leaf, 1, Leaf), 2, Node (Leaf,3,Leaf))) = [1;2;3] In [] let rec fold inorder f acc t = (* YOUR CODE HERE *) assert (fold_inorder (fun acc x -> acc @[x]) [] (Node (Node (Leaf, 1, Leaf), 2, Node (Leaf, 3, Leaf))) = [1;2;3]); assert (fold_inorder (fun acc x -> acc + x) 0 (Node (Node (Leaf, 1, Leaf), 2, Node (Leaf, 3, Leaf))) = 6)

Problem 8 We have seen the benefits of the 'fold' function for list data structures. In a similar fashion, write a function In [ ]: fold_inorder : 'a > 'b> 'a) -> 'a -> 'b tree -> 'a That does an inorder fold of the tree. The function should traverse the left subtree, visit the root, and then traverse the right subtree. For example, fold_inorder (fun acc x -> acc @ [x]) [] (Node (Node (Leaf, 1, Leaf), 2, Node (Leaf,3,Leaf))) = [1;2;3] In [] let rec fold inorder f acc t = (* YOUR CODE HERE *) assert (fold_inorder (fun acc x -> acc @[x]) [] (Node (Node (Leaf, 1, Leaf), 2, Node (Leaf, 3, Leaf))) = [1;2;3]); assert (fold_inorder (fun acc x -> acc + x) 0 (Node (Node (Leaf, 1, Leaf), 2, Node (Leaf, 3, Leaf))) = 6)

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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