Problem 8 to 9 The table below shows the number of M&Ms and Skittles in another class' candy mixture. Use the data in the table to answer each question. Purple Brown Total Red Yellow Green Blue Orange 6. 14 10 58 M&Ms 12 Skittles %3D 7 10 49 9. 21 Total 17 15 24 17 5 8 107
Permutations and Combinations
If there are 5 dishes, they can be relished in any order at a time. In permutation, it should be in a particular order. In combination, the order does not matter. Take 3 letters a, b, and c. The possible ways of pairing any two letters are ab, bc, ac, ba, cb and ca. It is in a particular order. So, this can be called the permutation of a, b, and c. But if the order does not matter then ab is the same as ba. Similarly, bc is the same as cb and ac is the same as ca. Here the list has ab, bc, and ac alone. This can be called the combination of a, b, and c.
Counting Theory
The fundamental counting principle is a rule that is used to count the total number of possible outcomes in a given situation.
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The table below shows the number of M&Ms and Skittles in another class' candy mixture. Use the data in the
table to answer cach question.
Problem 8 to 9
Blue
Purple
Brown
Total
Yellow
Green
Orange
6.
Red
8
58
14
10
M&Ms
12
49
10
7
7
15
Skittles
5
8
107
24
17
Total
21
17
8. Find P(Orange M & M)
Circle your answer below.
6
58
a. p(Orange |M &M} =
6 (b) P(Orange M & M)-
(c) P(Orange M & M)%3=
(d) P(Oronge|M & M%3D
107
107
9. Find P(Green | Skittle)
Circle your answer below.
10
10
24
(a) P(Green| Skitrie =
(b) P(Green Skinle)=
24
(c) r(Green| Sliule)=
49
49
(d) P(Green Skinle)=
107
49
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