Problem #7.9, page 216–A 2000-kg elevator with broken cables in a test rig is falling at 4.00 m/s when it contacts a cushioning spring at the bottom of the shaft. The spring is intended to stop the elevator, compressing 2.00 m (see below figure). During the motion, a safety clamp applied a constant 17,000-Nfriction force to the elevator. Neglect air drag. f = 17,000 N m = 2000 kg %3D U2 = 0 0 m/s Point 2.00 m
Problem #7.9, page 216–A 2000-kg elevator with broken cables in a test rig is falling at 4.00 m/s when it contacts a cushioning spring at the bottom of the shaft. The spring is intended to stop the elevator, compressing 2.00 m (see below figure). During the motion, a safety clamp applied a constant 17,000-Nfriction force to the elevator. Neglect air drag. f = 17,000 N m = 2000 kg %3D U2 = 0 0 m/s Point 2.00 m
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(a) Using the work-kinetic energy theorem, find the necessary force constant k for the spring
(b) Using the law of conservation of energy, find the necessary force constant k for the spring.
Transcribed Image Text:Problem #7.9, page 216–A 2000-kg elevator with broken cables in a test rig is falling at 4.00
m/s when it contacts a cushioning spring at the bottom of the shaft. The spring is intended to stop
the elevator, compressing 2.00 m (see below figure). During the motion, a safety clamp applied a
constant 17,000-Nfriction force to the elevator. Neglect air drag.
f = 17,000 N
m =
2000 kg
Uz = 0
%3D
4.00 m/s
Point 1
2.00 m
w=mg
Point 2
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