Problem 7.1: For the beam cross-section shown in Figure 7.12, estimate the shear force contribution of carbon fiber composite and total shear capacity,Y Compressive strength of concrete is 4000 psi. Assume U-wrap configuration, -0.0167, E-33x10 psi, and fiber thickness is 0.0065 in. (unidirectional). The steel stirrups consist of two- legged No. 3 bars at 12 in. center-t0-center. a) One ply, continuous strip b) One ply, 5 in. wide at 6 in. center-to-center ) Two plies, 5 in. wide (each) at 12 in. center-to-center d) One ply, 5 in. wide at 12 in. center-to-center

Structural Analysis
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Author:KASSIMALI, Aslam.
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Chapter2: Loads On Structures
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Problem 7.1: For the beam cross-section shown in Figure 7.12, estimate the shear force
1contribution of carbon fiber composite and total shear capacity.
strength of concrete is 4000 psi. Assume U-wrap configuration, sp-0.0167, E-33×10
psi, and fiber thickness is 0.0065 in. (unidirectional). The steel stirrups consist of two-
legged No. 3 bars at 12 in. center-t0-center.
V Compressive
a) One ply, continuous strip
b) One ply, 5 in. wide at 6 in. center-to-center
c) Two plies, 5 in. wide (each) at 12 in. center-to-center
d) One ply, 5 in. wide at 12 in. center-to-center
4 in.
17.5 in.
2-legged #3 bars U-
stirrups @ 12" c/c
2.5 in.
6 in.
Transcribed Image Text:Problem 7.1: For the beam cross-section shown in Figure 7.12, estimate the shear force 1contribution of carbon fiber composite and total shear capacity. strength of concrete is 4000 psi. Assume U-wrap configuration, sp-0.0167, E-33×10 psi, and fiber thickness is 0.0065 in. (unidirectional). The steel stirrups consist of two- legged No. 3 bars at 12 in. center-t0-center. V Compressive a) One ply, continuous strip b) One ply, 5 in. wide at 6 in. center-to-center c) Two plies, 5 in. wide (each) at 12 in. center-to-center d) One ply, 5 in. wide at 12 in. center-to-center 4 in. 17.5 in. 2-legged #3 bars U- stirrups @ 12" c/c 2.5 in. 6 in.
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