Problem 61 (Phasor transform) Given the circuit in Figure 6, find the value of R and L Given: ● ● H(₂51-+(1) 002 10 = (1) ³ R=2 L=? w m W M Ⓒu(t)=10¹√cos (wt + 30") V[ vs(t) = 10 √2 cos(wt +30°) V is(t) = 0.1 cos (wt -15°)A Ro=800 C=625nF=625 10°F w = 10^rad Figure 6 [R₁=80₁ = C = 625m
Problem 61 (Phasor transform) Given the circuit in Figure 6, find the value of R and L Given: ● ● H(₂51-+(1) 002 10 = (1) ³ R=2 L=? w m W M Ⓒu(t)=10¹√cos (wt + 30") V[ vs(t) = 10 √2 cos(wt +30°) V is(t) = 0.1 cos (wt -15°)A Ro=800 C=625nF=625 10°F w = 10^rad Figure 6 [R₁=80₁ = C = 625m
Introductory Circuit Analysis (13th Edition)
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ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
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Help with Phasor Transform: given the circuit , find the value of R and L

Transcribed Image Text:Problem 6
(Phasor transform)
Given the circuit in Figure 6, find the value of R and L
Given:
(51-0010-(1)
+1
R=2
W
L = ?
m
) US(t) = 10 √(√2 cos (wt + 30°) V[
vs(t) = 10 √2 cos(wt +30°) V
is(t) = 0.1 cos (wt -15°)A
Ro=800
C=625nF=625 10°F
w = 10^rad
Figure 6
R₁=80₁ = C = 62SmF
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