Problem 6: Energy Equation Demonstration Recently we saw a laboratory apparatus demonstrate several aspects of the energy equation. As you will recall, the cross-sectional area of the pipe varied from a maximum of 4.909×10+ m² at point A to 7.854x105 m² at point E (factor of 6.25 difference): 75.08 BCDE 51.0 74 35 5.0 Part A What is the smallest velocity at Point E (VE) that will cause cavitation? T = 20°C, and you may assume the pressure at Point A (PA) is one Denver atmosphere, so PA = Patm = 85 kPa. Neglect the piezometer connections - assume they do not exist. [m/s] Part B In reality, of course, we do have piezometer connections at points A-F. What happens in the real apparatus when the discharge equals the result from Part A? (≤25 words)

Structural Analysis
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Problem 6: Energy Equation Demonstration
Recently we saw a laboratory apparatus demonstrate several aspects of the energy equation. As
you will recall, the cross-sectional area of the pipe varied from a maximum of 4.909×104 m² at
point A to 7.854x105 m² at point E (factor of 6.25 difference):
76.08
BCDE
SLOB
74
35
5.0
Part A
What is the smallest velocity at Point E (VE) that will cause cavitation? T = 20°C, and you may
assume the pressure at Point A (PA) is one Denver atmosphere, so PA = Patm = 85 kPa. Neglect
the piezometer connections - assume they do not exist. [m/s]
Part B
In reality, of course, we do have piezometer connections at points A-F. What happens in the real
apparatus when the discharge equals the result from Part A? (≤25 words)
Transcribed Image Text:Problem 6: Energy Equation Demonstration Recently we saw a laboratory apparatus demonstrate several aspects of the energy equation. As you will recall, the cross-sectional area of the pipe varied from a maximum of 4.909×104 m² at point A to 7.854x105 m² at point E (factor of 6.25 difference): 76.08 BCDE SLOB 74 35 5.0 Part A What is the smallest velocity at Point E (VE) that will cause cavitation? T = 20°C, and you may assume the pressure at Point A (PA) is one Denver atmosphere, so PA = Patm = 85 kPa. Neglect the piezometer connections - assume they do not exist. [m/s] Part B In reality, of course, we do have piezometer connections at points A-F. What happens in the real apparatus when the discharge equals the result from Part A? (≤25 words)
Expert Solution
Step 1: Part A):

At point A and E,

applying the continuity equation,

straight A subscript straight A straight V subscript straight A equals straight A subscript straight E straight V subscript straight E
4.909 cross times 10 to the power of negative 4 end exponent straight V subscript straight A equals 7.854 cross times 10 to the power of negative 5 end exponent straight V subscript straight E
straight V subscript straight E equals 6.250 straight V subscript straight A

given pressure at straight P subscript straight A equals 85 space KPa equals 85 cross times 10 cubed space straight N divided by straight m squared

Cavitation: When the static pressure in the throat is lower than the vapor pressure of fine liquid a very rapid partial                                transition from liquid to gas phase occurs.

straight P subscript Sat space 20 to the power of straight o straight C space equals space 2.339 space KPa
The space pressure space must space be space jept space above space straight a space 2.339 space to space avoid space cavitation.

By applying Bernoulli's equation at A and E

fraction numerator straight P subscript straight A over denominator straight rho subscript straight w straight g end fraction plus fraction numerator straight V subscript straight A superscript 2 over denominator 2 straight g end fraction plus straight Z subscript straight A minus fraction numerator straight P subscript straight E over denominator straight rho subscript straight w straight g end fraction plus fraction numerator straight V subscript straight E superscript 2 over denominator 2 straight g end fraction plus straight Z subscript straight E equals 0
straight Z subscript straight A equals straight Z subscript straight E
fraction numerator straight P subscript straight A minus straight P subscript straight E over denominator straight rho subscript straight w straight g end fraction minus fraction numerator straight V subscript straight E superscript 2 minus straight V subscript straight A superscript 2 over denominator 2 straight g end fraction
fraction numerator 85 cross times 10 cubed minus 2.339 cross times 10 cubed over denominator 998.23 end fraction equals fraction numerator left parenthesis 6.25 space straight V subscript straight A right parenthesis squared minus straight V subscript straight A superscript 2 over denominator 2 end fraction
82.8 equals 19.03 space straight V subscript straight A superscript 2
straight V subscript straight A superscript 2 equals 4.35
straight V subscript straight A superscript blank equals 2.085 space straight m divided by straight s

straight V subscript straight E equals 6.25 space straight V subscript straight A superscript blank
straight V subscript straight E equals 13.03 space straight m divided by straight s

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