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Problem 6 e3 = ê2-e3 point P' = ₁ + 2ê2 + 3 in the orginal basis. ê₁ = 2ê1 (a) A new basis is given as ê2 = ê2 +ê3. Find the O(A)P= 2 3 2 O(B)P= 3 1 O(C)P= 1 0 O(D)P= 1 3 O(E)P= 3 cont. basis. (b) Find the point Q = ê₁ + 2ê2 + ê3 in the new O(A)Q' = O(B)Q' = O(C)Q' = 1 2 1/2) 3/2 1/2, 0 1 1/2 O(D)Q' = 1 3 2 /1/2 3 1 O(E)Q' =

Problem 6 e3 = ê2-e3 point P' = ₁ + 2ê2 + 3 in the orginal basis. ê₁ = 2ê1 (a) A new basis is given as ê2 = ê2 +ê3. Find the O(A)P= 2 3 2 O(B)P= 3 1 O(C)P= 1 0 O(D)P= 1 3 O(E)P= 3 cont. basis. (b) Find the point Q = ê₁ + 2ê2 + ê3 in the new O(A)Q' = O(B)Q' = O(C)Q' = 1 2 1/2) 3/2 1/2, 0 1 1/2 O(D)Q' = 1 3 2 /1/2 3 1 O(E)Q' =

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Problem 6 ê₁ = 2ê₁ (a) A new basis is given as ê2 = ê2 +ê3. Find the e3= 22-23 point P' = ê + 2ê2 + 3 in the orginal basis. O(A)P = 2 3 2 O(B)P= 3 1 1 O(C)P= O(D)P= cont. O(E)P= 3 basis. O(A)Q' = (b) Find the point Q = ê1 + 2ê2 + ê3 in the new O(B)Q' = O(C)Q' = 0 O(D)Q' = 3 O(E)Q' = 3 2 1/2 3 1 0 1 2 1/2 3/2 1/2 0 1 1/2
Transcribed Image Text:Problem 6 ê₁ = 2ê₁ (a) A new basis is given as ê2 = ê2 +ê3. Find the e3= 22-23 point P' = ê + 2ê2 + 3 in the orginal basis. O(A)P = 2 3 2 O(B)P= 3 1 1 O(C)P= O(D)P= cont. O(E)P= 3 basis. O(A)Q' = (b) Find the point Q = ê1 + 2ê2 + ê3 in the new O(B)Q' = O(C)Q' = 0 O(D)Q' = 3 O(E)Q' = 3 2 1/2 3 1 0 1 2 1/2 3/2 1/2 0 1 1/2
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