part D E Utility5,000KVAUtilityGenX=0.15X= 0.06X- 0.15X = 0.15X = 0.06X = 0.15X- 0.1Xo = 0.04X= 0.1Plant Distribution BusPlant Distribution Bus(a)(b)5,000KVAUtilityulyGenX= 0.06x,-0.15X = 0.06X = 0.15Xo = 0.04X- 0.1%3DPlant Diatribution Bus(c)Figure (4) Single-line diagrams for Problem 6 Problem 6a- Explain the reasons for applying system grounding in electric power systems.Consider the industrial plant distribution bus which is supplied by a utility source with per-unitsequence reactances as shown in Figure (4-a). Assume that all reactances are given on a 5,000-kVAbase, and that the plant's bus voltage is 4,160-V.b- Determine the fault current for a single line to ground fault on phase A of the bus.Assume now that an ungrounded 5,000 kVA generator is added at the distribution bus as shown inFigure (4-b).c- Determine the fault current for a single line to ground fault on phase A of the bus.Assume now that the utility transformer is grounded through a 8 2 grounding resistor as shown inFigure (4-c.)d- Determine the value of the grounding resistor in per unit.e- Determine the fault current for a double line to ground fault on phases B and C of the bus.

The current flowing through a circuit during a fault condition is called fault current. Fault types…

Problem 6 a- Explain the reasons for applying system grounding in electric power systems. Consider the industrial plant distribution bus which is supplied by a utility source with per-ur sequence reactances as shown in Figure (4-a). Assume that all reactances are given on a 5,000-kV base, and that the plant's bus voltage is 4,160-V. b- Determine the fault current for a single line to ground fault on phase A of the bus. Assume now that an ungrounded 5,000 kVA generator is added at the distribution bus as shown in Figure (4-b). C- Determine the fault current for a single line to ground fault on phase A of the bus. Assume now that the utility transformer is grounded through a 8 2 grounding resistor as shown in Figure (4-c.) d- Determine the value of the grounding resistor in per unit. e- Determine the fault current for a double line to ground fault on phases B and C of the bus.

Problem 6 a- Explain the reasons for applying system grounding in electric power systems. Consider the industrial plant distribution bus which is supplied by a utility source with per-ur sequence reactances as shown in Figure (4-a). Assume that all reactances are given on a 5,000-kV base, and that the plant's bus voltage is 4,160-V. b- Determine the fault current for a single line to ground fault on phase A of the bus. Assume now that an ungrounded 5,000 kVA generator is added at the distribution bus as shown in Figure (4-b). C- Determine the fault current for a single line to ground fault on phase A of the bus. Assume now that the utility transformer is grounded through a 8 2 grounding resistor as shown in Figure (4-c.) d- Determine the value of the grounding resistor in per unit. e- Determine the fault current for a double line to ground fault on phases B and C of the bus.

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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