Problem 5.60 Given: air discharges downward in the pipe then outward between the parallel disks, assuming negligible density change in the air, derive a formula for the acceleration of air at point A, which is a distance r from the center of the disks. Express the acceleration in terms of the constant air discharge Q, the radial distance r, and the disk spacing h. V D elevation view A plan view D=10 cm, h = 0.6 cm, Q=0.380 m²/s, r = 20 qv Find: What are the velocity in the pipe and the acceleration at point A? Derive a formula for acceleration at Point A.
Problem 5.60 Given: air discharges downward in the pipe then outward between the parallel disks, assuming negligible density change in the air, derive a formula for the acceleration of air at point A, which is a distance r from the center of the disks. Express the acceleration in terms of the constant air discharge Q, the radial distance r, and the disk spacing h. V D elevation view A plan view D=10 cm, h = 0.6 cm, Q=0.380 m²/s, r = 20 qv Find: What are the velocity in the pipe and the acceleration at point A? Derive a formula for acceleration at Point A.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Not sure how to do this one. Would appreciate a full solution, thanks!
Textbook Answer: v = 48.4 m/s, a = -12700 m/s^2
Transcribed Image Text:Problem 5.60
Given: air discharges downward in the pipe then outward
between the parallel disks, assuming negligible density
change in the air, derive a formula for the acceleration.
of air at point A, which is a distance r
a distance r from the
center of the disks. Express the acceleration in terms
of the constant air discharge Q, the radial distance
r, and the disk spacing h.
_o
r
↑
elevation view
A
plan view
D=10 cm₁ h = 0.6cm, Q= 0.380 m ² /s, v= 20 cm
Find: What are the velocity in the pipe and the acceleration
at point A? Derive a formula for acceleration at Point A.
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