Problem 5.15 Time-limited signals cannot be bandlimited, but their rate of decay in the fre- quency domain depends on the sharpness of the transitions in the time domain. For each of the time-limited signals below, estimate the rate of decay of |Â(f)| as |f gets large. You should be able to answer this without detailed computation of the Fourier transform. (a) x₁(t) = (2|t|) I[-2,2] (t). (b) x2(t) = tI-2,2] (t). (c) x3 (t) = cos(πt/4) 1-2,2] (t).

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Time-limited signals cannot be bandlimited, but their rate of decay in the frequency domain depends on the sharpness of the transitions in the time domain. For each of the time-limited signals below, estimate the rate of decay of |Xb(f)| as |f| gets large. You should be able to answer this without detailed computation of the Fourier transform. (a) x1(t) = (2 − |t|)I[−2,2](t). (b) x2(t) = |t|I[−2,2](t). (c) x3(t) = cos(πt/4)I[−2,2](t). please have a step by step solution for each of them

Problem 5.15 Time-limited signals cannot be bandlimited, but their rate of decay in the fre-
quency domain depends on the sharpness of the transitions in the time domain. For each of the
time-limited signals below, estimate the rate of decay of Â(ƒ)| as |ƒ| gets large. You should be
able to answer this without detailed computation of the Fourier transform.
(a) x₁(t) = (2|t|) I[-2,2] (t).
(b) x2(t) = tI-2,2] (t).
(c) x3 (t) = cos(πt/4) 1-2,2] (t).
Transcribed Image Text:Problem 5.15 Time-limited signals cannot be bandlimited, but their rate of decay in the fre- quency domain depends on the sharpness of the transitions in the time domain. For each of the time-limited signals below, estimate the rate of decay of Â(ƒ)| as |ƒ| gets large. You should be able to answer this without detailed computation of the Fourier transform. (a) x₁(t) = (2|t|) I[-2,2] (t). (b) x2(t) = tI-2,2] (t). (c) x3 (t) = cos(πt/4) 1-2,2] (t).
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