Problem 5: When making a heater, one side is often against a surface which you don't want to be heated. One way to prevent heating that side is to insulate that side of the heater such that most of the heat power is directed to the side you do want heated. An example of that is below. What is the heat flux to the left side of the heater blanket? Neglect the thickness of the blanket (Omm). Treat it as infinitely thin. T01 = 25°C W h1 = 12 m²K T2 = 60°C W = 30 m²K Heater Blanket G10 Silicone Silicone Aluminum h2 q = 2000W 3mm 4mm Omm 2mm 3mm

Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
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Thermal Conductivity of G10 fiberglass is 0.3 silcone is 0.2 aluminum is 200

Problem 5: When making a heater, one side is often against a surface which you don't want to be
heated. One way to prevent heating that side is to insulate that side of the heater such that most of the
heat power is directed to the side you do want heated. An example of that is below. What is the heat
flux to the left side of the heater blanket? Neglect the thickness of the blanket (0mm). Treat it as
infinitely thin.
To2 = 60°C
W
T01 = 25°C
W
h, = 12
m²K
Heater Blanket
Aluminum h2 = 30
m²K
G10
Silicone
Silicone
q = 2000W
3mm
4mm
Omm
2mm
3mm
Transcribed Image Text:Problem 5: When making a heater, one side is often against a surface which you don't want to be heated. One way to prevent heating that side is to insulate that side of the heater such that most of the heat power is directed to the side you do want heated. An example of that is below. What is the heat flux to the left side of the heater blanket? Neglect the thickness of the blanket (0mm). Treat it as infinitely thin. To2 = 60°C W T01 = 25°C W h, = 12 m²K Heater Blanket Aluminum h2 = 30 m²K G10 Silicone Silicone q = 2000W 3mm 4mm Omm 2mm 3mm
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