Problem 5 Determine the magnitudes of the components of the force acting along the axis AB of the wrench handle and perpendicular to it. Son Can toa 300 mm x B Ⓒ = 128° (0,0,300) 500 mm UF = cos 30%. Sin 45 i = -0.6124; + 0.6124j F = 80 N 30 45" (0,500, 300) + Cos 30° cos 45j+ sin 30 + 0.5k UAB = -j Cos 0 = UF • UAB = (-.61241 +0.61245 +95 k) (-j) I How do we go from this = -0.6124 to this?
Problem 5 Determine the magnitudes of the components of the force acting along the axis AB of the wrench handle and perpendicular to it. Son Can toa 300 mm x B Ⓒ = 128° (0,0,300) 500 mm UF = cos 30%. Sin 45 i = -0.6124; + 0.6124j F = 80 N 30 45" (0,500, 300) + Cos 30° cos 45j+ sin 30 + 0.5k UAB = -j Cos 0 = UF • UAB = (-.61241 +0.61245 +95 k) (-j) I How do we go from this = -0.6124 to this?
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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Transcribed Image Text:Problem 5
Determine the magnitudes of the components of the force
acting along the axis AB of the wrench handle and
perpendicular to it.
Son Can toa
300 mm
x
B
9 = 128°
(0,0,300)
500 mm
UF = COS 30%. Sin us i
= -0.6124; + 0.6124j
F = 80 N
30
5
45"
+ Cos 30° cos 45j+ sin 30
+ 0.5k
(0,500, 300)
UAB = -j
Cos 0 = UF • UAB = (-.61241 - 0.61245 +95 k) (-j)
I How do we go from this
= -0.6124
to this?
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