PROBLEM 5: A grade of -2.7% grade intersects a grade of +1.6% at Station 12 + 252.10 of elevations 20.21 meters. These two center grade lines are to be connected by a 111-meter symmetrical vertical parabolic curve. 1. Find the distance of the lowest point from PVC. 2. At what station will the cross-drainage pipes be situated? 3. Find the vertical distance between PC and PI. 4. Find the vertical distance between PC and the lowest point. 5. If the overall outside dimensions of the reinforced concrete pipe to be installed is 100 cm, and the top of the culvert is 50 cm below the subgrade, what will be the invert elevation at the center?
PROBLEM 5: A grade of -2.7% grade intersects a grade of +1.6% at Station 12 + 252.10 of elevations 20.21 meters. These two center grade lines are to be connected by a 111-meter symmetrical vertical parabolic curve. 1. Find the distance of the lowest point from PVC. 2. At what station will the cross-drainage pipes be situated? 3. Find the vertical distance between PC and PI. 4. Find the vertical distance between PC and the lowest point. 5. If the overall outside dimensions of the reinforced concrete pipe to be installed is 100 cm, and the top of the culvert is 50 cm below the subgrade, what will be the invert elevation at the center?
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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PROBLEM 5: A grade of -2.7% grade intersects a grade of +1.6% at Station 12 + 252.10 of elevations 20.21 meters.
These two center grade lines are to be connected by a 111-meter symmetrical vertical parabolic curve.
1. Find the distance of the lowest point from PVC.
2. At what station will the cross-drainage pipes be situated?
3. Find the vertical distance between PC and PI.
4. Find the vertical distance between PC and the lowest point.
5. If the overall outside dimensions of the reinforced concrete pipe to be installed is 100 cm, and the top of the
culvert is 50 cm below the subgrade, what will be the invert elevation at the center?
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