Problem 5 20kN Two couple forces (20kN and F) act on the beam. 1. Find the magnitude of F so that the resultant couple moment is 50kN.m. clockwise. 2. Find the resultant couple force. 3. Find the distance between the resultant couple force. F 1.5m 0.75m 20kN
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- Two couple forces (20kN and F) act on the beam. a. Find the magnitude of F so that the resultant couple moment is 40kN.m. clockwise. b. Find the resultant couple force.3. Find the distance between the resultant couple force.2. Find the resultant couple. 2 ft 2 ft 2 ft 300 lb 150 lb -2 ft-2 ft- 30% √30⁰ 150 lb 300 lbc. Find the moment of the forces about point A. d. Find the shortest distance 30 800 N between the lines of action of the two forces. 200 mm G00 mm 30 20 800 N
- Given: three forces act on a particle P. Force A has a magnitude of 55lbs and acts 30 degrees CCW from the x-axis. Force B has a magnitude of 70 lbs and acts along a ray from point P with a slope at 1/-4. Force C has a magnitude of 55 lbs lbs and acts straight left. Add the three vectors to find the magnitude of the resultant force R and the angle it makes with the positive a-axis 0.3. Find the resultant and the location of the following parallel force system. A150 lb |lo lb solb 7516. A TITINIA ft. íz ft.#Q1: Determine the moment of 50N force shown in Fig. about point O by at least two ways? 50N 100 mm 200 mm 45 100 mm * Q2: determine the value of F Which effect with other two forces as shown in Fig. if the Resultant these forces are 80 N and acting along u- axis. Note that: Cos2e + Sin20 = 1 S0 Ib 45° 90 lb
- Q1: The magnitude of force vector F is given as 160 N. 15 m B a. Represent force F in terms of its Cartesian component vectors. 18 m b. Consider axis CD. Find out a component vector of F which is parallel, and another component vector which is perpendicular to axis CD. D 25 mThe resultant of the concurrent forces has a magnitude of 800 N passing through points (x₁ = 1, y₁ = 1, z₁ = 1) and (x₂ = 2, y₂ = 3, z₂ = 4). 1. Compute the x- component of the resultant force. a. 371.1 N b. 392.31 N c. 422.6 N d. 213.81 N 2. Compute the y – component of the resultant force. a. 512.92 N b. 556.62 N c. 427.62 N d. 634.72 N 3. Compute the z – component of the resultant force. a. 632.73 N b. 641.43 N c. 742.13 N d. 791.43 NQ2:- For the block shown in the figure below, the 40 lb. force is passing through points EF, the 50 Ib. force is passing throuch points JB, and the force 20 lb. is passing through point C. 1. Find the resultant force and its directions. 2. Determie the resultant moment of three forces in Figure about the x-axis, the y-axis, and the z-axis. 20 ib 50 lb 40 lb 3 dimensions in inch
- Q1:- For the two force systems shown below, find the following: 1. The resultant force and its directions. 2. The resultant moment about the origin. 3. The resultant moment with respect to line OA shown below. 2 ft- 2 ft 2 ft A F = 500 lb 4 ft F = 7004 2 ft F2 = 800 lbFind the Moment of the Couple at Point A 1 unit 1 ft 200 lbs 200 Ibs Find the Moment of the Couple at Point A 1 unit1t 200 bs 200 lbsThe force R is the resultant of P and 0. Determine Q and the angle .