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Problem 42 IR Spectrum (liquid film) 1768 W 1746 1190 2000 21 4000 3000 1600 1200 800 v (cm") 100 Mass Spectrum 80 60 29 40 20 M*'= 146 (<1%) C6H10 04 40 80 120 160 200 240 280 m/e 13C NMR Spectrum (50.0 MHz, CDCI, solution) DEPT CH,t CH, сн solvent proton decoupled 200 160 120 80 40 O 8 (ppm) 'H NMR Spectrum (200 MHz, CDCI, solution) TMS 10 9 8 6 5 4 3 2 1 8 (ppm) 131 % of base peak

Problem 42 IR Spectrum (liquid film) 1768 W 1746 1190 2000 21 4000 3000 1600 1200 800 v (cm") 100 Mass Spectrum 80 60 29 40 20 M*'= 146 (<1%) C6H10 04 40 80 120 160 200 240 280 m/e 13C NMR Spectrum (50.0 MHz, CDCI, solution) DEPT CH,t CH, сн solvent proton decoupled 200 160 120 80 40 O 8 (ppm) 'H NMR Spectrum (200 MHz, CDCI, solution) TMS 10 9 8 6 5 4 3 2 1 8 (ppm) 131 % of base peak

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Problem 42 IR Spectrum (liquid film) 1768 W 1746 1190 2000 21 4000 3000 1600 1200 800 v (cm' 100F 80 60 Mass Spectrum 29 40 20 M*'= 146 (<1%) C3H10 04 40 80 120 160 200 240 280 m/e 13C NMR Spectrum (50.0 MHz, CDCI, solution) DEPT CH CH, сн solvent proton decoupled 200 160 120 80 40 0 8 (ppm) 1H NMR Spectrum (200 MHz, CDCI, solution) TMS 10 9 8 7 6 4 2 1 8 (ppm) 131 % of base peak
Transcribed Image Text:Problem 42 IR Spectrum (liquid film) 1768 W 1746 1190 2000 21 4000 3000 1600 1200 800 v (cm' 100F 80 60 Mass Spectrum 29 40 20 M*'= 146 (<1%) C3H10 04 40 80 120 160 200 240 280 m/e 13C NMR Spectrum (50.0 MHz, CDCI, solution) DEPT CH CH, сн solvent proton decoupled 200 160 120 80 40 0 8 (ppm) 1H NMR Spectrum (200 MHz, CDCI, solution) TMS 10 9 8 7 6 4 2 1 8 (ppm) 131 % of base peak
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